Suppose the distance is X kmthen at 40 km/h the car will take 60*X/40 minutes.
and at 50 km/h the car will take 60*X/50 minutes.
The difference between these amounts of time is 11 - 5 = 6 minutes.
So 60X/40 - 60X/50 = 11
3X/2 - 6x/5 = 11
15X - 12X = 110
3X = 110 and so X = 110/3 = 36 2/3 km.
v = velocity/60 to get speed per minutes = vt = 40/60 x (t+11)s = vt = 50/60 x (t+5)since distance is the same 40t + 440 = 50t + 25010t = 190t = 19 minutess = 40/60(19+11) = 20 km
let the distanncccee covered by both be 'S' km. And time taken by A be 'x' min.. therefore time taken by B is 'x+6' min. 8x=(x+6)10 8x=10x+60 -2x=60 x=-60/2 x=-30 distance can not be negetive, so x=30 i.e, distance travelled is 30 km.
if the bal is thrown by making 45 degree angles. with the ground..it will travel maximum distance...
The amplitude of a pendulum is the distance between its equilibrium point and the farthest point that it reaches during each oscillation.
8:08am when train b reaches the station the distance from train a is 12 miles. the relative speed between the trains is 20mph passing 12 miles in 20mph takes 0.6 hours which is 36 minutes. 36 minutes after 7:32 is 8:08
Your stopwatch can't count on any longer after it reaches 1000 hours.
It is 2.5 km.
That depends on how far away the next destination is and how fast the tornado is traveling.
The point in a planet's orbit where it reaches its maximum distance from the Sun is called the Aphelion.
The lunar Vehicle is what makes it to the Final Fronter
In second-degree heart block, not every impulse reaches its destination.
When the barge on the Erie Canal reaches Lake Erie, the goods or people need to be transferred to a boat to go to the next destination.
You can use the ping command to verify connectivity. Additionally you can use traceroute to determine how the packet reaches that destination.
CCNA Guide to Cisco Networking 4th Edition Answer: A; progressively higher TTL values until a packer reaches the destination.
This might not be completely accurate but I'm positive this is the general idea. A space probe is launched from a rocket. When the rocket reaches a certain distance into space, parts of the rocket that aren't necessary to carry the probe to its destination break loose from the rocket.
Since 1 AU is the distance from the Sun to the Earth and it takes about 8 Minutes for light to travel such a distance this problem can be solved by simple multiplication and division.(50,000 AU)(8 Minutes)=400,000 Minutes/60 (Minutes/Hour)=6666.67 Hours/24 (Hours/Earth Day)=277.78 DaysSo the answer is 277.78 Earth Days or 0.76 Earth Years!
The question says that the person traveling slower reaches the destination 30 minutes earlier than the person traveling faster. If the travelers depart at the same time, then this outcome is impossible in the real world. But the question gives no information concerning their relative times of departure. There is either a typographical error in the question as presented above, or else vital information is missing. As it appears above, the question can't be answered.
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