The length of the rectangle is 20 ft. The area of the rectangle is 11 * 20 = 220 square ft.
The area of a parallelogram is the length times the vertical height. In a rectangle, the vertical height is the same as the width so the area is length times width.
Length times Height
A rectangle is a two dimensional object, with length and width but not height. An object with length, width and height could be a cuboid, in which case is it still the area that is required or the volume?
The area of rectangle is : 60.0
Height = Area divided by Length
A rectangle is a good, simple shape to begin with. The area of a rectangle is equal to the product of the length of its base and the length of its height. The height is a segment that is perpendicular to the base. For a rectangle, the base and height are often called the "length" and the "width", and sometimes the height is referred to as the "altitude."
There is no "height" of a rectangle, unless it's a rectangular prism. Do you mean the length? If you have the area of the rectangle, the equation should be:A= L x WPlug in the area and the length and solve for the width, or plug in the area the width of the rectangle, and solve for the length.
The length of the rectangle is 20 ft. The area of the rectangle is 11 * 20 = 220 square ft.
The area of a parallelogram is the length times the vertical height. In a rectangle, the vertical height is the same as the width so the area is length times width.
Because the area of a parallelogram is length times perpendicular height and the area of a rectangle is also length times perpendicular height
Length times Height
You need the length AND the height in order to find the area
The relationship between the area of a triangle and a rectangle is a Triangle is base times height divided by 2. Area of a rectangle is length times height.
To work out the area of a rectangle, multiply the length and the width. Therefore: Area=23*20=460
A rectangle is a two dimensional object, with length and width but not height. An object with length, width and height could be a cuboid, in which case is it still the area that is required or the volume?
Area