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If we insist on the condition that all the numbers must be integers... The only way this can happen is if the quotient and one of the other numbers are negative. For example, if the original numbers are -4 and 2, then their sum is -2, and the quotient of -4 divided by 2 is also -2. I believe that's the only integer example of a set of numbers satisfying that criterion.
(1) x + y = 15(2) x/y = 14Solving (1) and substituting in (2)...x = 15 - y15-y/y = 1414y = 15 - y15y = 15y = 1x = 14================================The sum of 1 + 14 = 15The quotient of 14/1 = 14
2 and 1.
The "quotient" of two numbers is the result of a multiplication sum. Therefore, if 6x = -12, then x = -2.