Brief answer: yes.
Detailed answer:
First, the definition of an rational number. Given any two ordered pair of integers (m,n), (p,q) with n,q !=0, define a relation (m,n)~(p,q) if and only if mq =np over the integers. The equivalence class of (m,n), denoted [m,n] defined as {(p,q):(p,q)~(m,n)}. Then the set of all equivalence classes is the rational numbers Q:={[m,n]:m,n are integers, n not equal to 0}. And the relation ~ over pairs of integers becomes = as [m,n]=[p,q] if and only if (m,n) ~ (p,q).
But the notation [m,n] is too ugly, so we write it as m/n instead. Read m over n, or m divided by n, now we have division defined as well.
Now consider if we create a map f that sends integers into the rationals. f(k) = [k,1] for all integer k, we claim this is a good way of "inscribing" integers into the rationals. That is for every k, there is one and only one class [k,1], this is easy. And for every class of the form [b,1], we can find integer b that maps to it.
Now if we just imagine that [k,1] is actually just k, then here we go, integers are "in" rational numbers too!
-1763 is an integer.
Yes, 0/3 is 0 which is a rational number
Rational.
1/4, or .25 is rational.
No.
No. Anything over 0 is not a defined number.
Yes, it is.
Rational numbers are all whole numbers over 0. It basically means that if you want to say how much cats you have, you use rational numbers. You don't have -8 cats, you don't have 0 cats and hopefully you don't have 3.5 cats. You have 4 cats. There are infinite rational numbers.
Yes. 0 divided by any real number (including rational numbers, which are a subset of the real numbers) is 0.
Yes. 0.3 with a bar over it is 1/3, which is a rational number.
.4/.8 is the same as 1/2 which is a rational number
Yes.
Infinitely many.