No. To be divisible by 6 the number must be divisible by both 2 and 3. To be divisible by 2, the last digit of the number must be even (ie one of {0, 2, 4, 6, 8}). The last digit of 35 is 5 which is not even and so 35 is not divisible by 2. To be divisible by 3, sum the digits of the number and if this sum is divisible by 3 then so is the original number. As the test can be applied to the sum, repeatedly summing the digits of the sums until a single digit remains, then the original number is divisible by 3 only if this single digit is one of {3, 6, 9}. For 35 3 + 5 = 8 which is not divisible by 3 (nor is is one of {3, 6, 9}, thus 35 is not divisible by 3. As 35 is not divisible by both 2 and 3 (in fact it is divisible by neither 2 nor 3) it is not divisible by 6.
numbers which are divisible by 35 and 40 = 280, 560, ...Get the LCM of 35 and 40.Prime factorization of:35 = 5 x 740 = 5 ......x 2 x 2 x 2===============LCM=5 x 7 x 2 x 2 x 2 = 280Then get the multiples of 280: 280, 560,...
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
The numbers that are divisible by 35 are infinite. The first four are: 35, 70, 105, 140 . . .
Yes, evenly 5 times. 35 is also divisible by: 1, 5 and 35.
No. 35 is not evenly divisible by two.
35 is not divisible by 2, making it an odd number.
No. To be divisible by 6 the number must be divisible by both 2 and 3. To be divisible by 2, the last digit of the number must be even (ie one of {0, 2, 4, 6, 8}). The last digit of 35 is 5 which is not even and so 35 is not divisible by 2. To be divisible by 3, sum the digits of the number and if this sum is divisible by 3 then so is the original number. As the test can be applied to the sum, repeatedly summing the digits of the sums until a single digit remains, then the original number is divisible by 3 only if this single digit is one of {3, 6, 9}. For 35 3 + 5 = 8 which is not divisible by 3 (nor is is one of {3, 6, 9}, thus 35 is not divisible by 3. As 35 is not divisible by both 2 and 3 (in fact it is divisible by neither 2 nor 3) it is not divisible by 6.
35 is not divisible by 3.
this # is divisible by 3, 5, and 9 :-) ;-P
no, it is divisible by 1, 2, 5, 7, 10, 14, 35, 70
No.2,345 is divisible by 1, 5, 7, 35, 67, 335, 469, 2345.
numbers which are divisible by 35 and 40 = 280, 560, ...Get the LCM of 35 and 40.Prime factorization of:35 = 5 x 740 = 5 ......x 2 x 2 x 2===============LCM=5 x 7 x 2 x 2 x 2 = 280Then get the multiples of 280: 280, 560,...
35 is divisible by 5 because any number that ends in 5 is divisible by 5.
The numbers that are divisible by 35 are infinite. The first four are: 35, 70, 105, 140 . . .
Yes, evenly 5 times. 35 is also divisible by: 1, 5 and 35.
35, and 70.