Yes, 405 is divisible by 1, 3 , 5, 9 , 15, 27, 45, 81, 135, 405.
1215 is divisible by 3 because its digits add up to a multiple of 3. That leaves 405. 405 is divisible by 3, leaving 135. 135 is divisible by 3, leaving 45. 45 is divisible by 3, leaving 15. 15 is divisible by 3, leaving 5. 5 is divisible by 5 because it ends in 5. 3 x 3 x 3 x 3 x 3 x 5 = 1215
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
Using the tests for divisibility:Divisible by 3:Add the digits and if the sum is divisible by 3, so is the original number: 6 + 8 + 4 = 18 which is divisible by 3, so 684 is divisible by 3Divisible by 6:Number is divisible by 2 and 3: Divisible by 2:If the number is even (last digit divisible by 2), then the whole number is divisible by 2. 684 is even so 684 is divisible by 2.Divisible by 3:Already shown above to be divisible by 3. 684 is divisible by both 2 & 3 so 684 is divisible by 6Divisible by 9:Add the digits and if the sum is divisible by 9, so is the original number: 6 + 8 + 4 = 18 which is divisible by 9, so 684 is divisible by 9Thus 684 is divisible by all 3, 6 & 9.
Numbers such as 135, 270, 405, and other multiples of 135.
Only 3 and 9 are divisible by 405.
Yes, 405 is divisible by 1, 3 , 5, 9 , 15, 27, 45, 81, 135, 405.
To determine if 405 is divisible by 2, we check if it is even, which it is not, so it is not divisible by 2. To check for divisibility by 3, we sum the digits of 405 (4+0+5=9), and since this sum is divisible by 3, 405 is divisible by 3. For divisibility by 5, we check if the last digit is 0 or 5, which it is, so 405 is divisible by 5. To check for divisibility by 9, we sum the digits again (4+0+5=9), and since this sum is divisible by 9, 405 is divisible by 9. Lastly, for divisibility by 10, we check if the number ends in 0, which it does, so 405 is divisible by 10.
405 is divisible by: 1, 3, 5, 9, 15, 27, 45, 81, 135, 405.
405 = 3 x 135 = 3 x 3 x 45 = 3 x 3 x 3 x 15 = 3 x 3 x 3 x 3 x 5, so it's divisible by 1, 3, 5, 9, 15, 27, 45, 81, 135 and 405 It is divisible by 9 because its digits add up to 9
yes
Try dividing on a calculator, for example, 405 / 2, 405 / 3, etc. If you get a whole number (no digits after the decimal point), it's divisible. Otherwise it isn't.
Yes 405 is divisible by 15 and the answer is 27.
No. 405 is not evenly divisible by ten.
Both are divisible by 3.
To find out if a number is divisible by 3 add up all it's digest and check if the total is divisible by 3. to check if a number is divisible by 2 check if the last digit is divisible by 2. So one such number is 405.
The LCM is 405.