124 is divisible by 4
268 is divisible by 1, 2, 4, 67, 134, 268.
There is no digit that can replace the ? in 2?67 to make it divisible by 4. All multiples of 4 are even, 2?67 is an odd number and so cannot be a multiple of 4.
Yes. It goes in 67 times.
The numbers that are divisible by 67 are infinite. Four of them are: 67, 134, 201, 268.
268 is divisible by 2, 4, 67, 134, and 268.
Yes, but not evenly, quotient is 67 and remainder is 4
1, 2, 4, 67, 134, 268
1, 2, 4, 67, 134, 268.
Yes, 67 is only divisible by 67 and 1.
By itself, 67.
268 is divisible by 1, 2, 4, 67, 134, 268.