Probability of pass on second attempt is 40% x 80% = 32%
60
depends who sets the 'pass level' and maybe what the subject is. 70% sounds high enough to pass though
after inspection of fabric based on 4 point system how to calculate the % of fabric pass or fail
Well that depends, if it's 60 over 100 then that's a sure pass but if it's 60 over 400 then that's an extreme failure.
Probability of pass on second attempt is 40% x 80% = 32%
You can fail, pass, pass with credit, pass with distinction or 100 percent
F is a Fail (under 60%), so a D which is 60% or higher is a pass.
You fail
english fail 100-80=20 only eng fail=20-10=10 hindi fail 100-70=30 only hindi fail=30-10=20 so overall fail=20+10+10=40 pass =60% so total_strength*60/100=144 solving we get total_strength=240
You need a 24 out of 30 to pass if you get 23 or lower you fail.
60
depends who sets the 'pass level' and maybe what the subject is. 70% sounds high enough to pass though
Say the mark is in cell B3, then the function would be as follows: =IF(B3>=50,"Pass","Fail")
It depends entirely upon the exam, but it is highly unlikely to be that low. In the course I am currently doing, the pass mark is 40%, so 28% is a fail and not a C (although only published as a pass/fail, individual percentages are given and a C would probably be something like 60%).
Assuming the 78 is 80% of the class and a 60 is passing: 78*.80 + x*.20 = 60 .2x + 62.4 = 60 .2x = -2.4 x = -12 So you cannot really fail the class. (If you need a 70 to pass the class you need at least a 38.)
60%