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A number is divisible by 3 if, and only if, the sum of its digits is also divisible by 3.
The test can be repeated on the sum, so repeatedly sum the digits until a single digit remains; only if this digit is 3, 6, 9 will the original number be divisible by 3.
For 988876:
988876 → 9 + 8 + 8 + 8 + 7 + 6 = 46
46→ 4 + 6 = 10
10 → 1 + 0 = 1
1 is none of {3, 6, 9}, thus 988876 is not divisible by 3
The remainder when 988876 is divided by 3 is 1.
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If x is an integer divisible by 3 then is x2 divisible by 3?
Yes, if x is an integer divisible by 3, then x^2 is also divisible by 3. This is because for any integer x, x^2 will also be divisible by 3 if x is divisible by 3. This can be proven using the property that the square of any integer divisible by 3 will also be divisible by 3.
Are all numbers divisible by 3 also by 9 give example?
All numbers divisible by 3 are NOT divisible by 9. As an example, 6, which is divisible by 3, is not divisible by 9. However, all numbers divisible by 9 are also divisible by 3 because 9 is divisible by 3.
Is 3215 divisible by 3?
Not evenly. A number is divisible by 3 if the sum of its digits is divisible by 3.
Is 416 divisible by 2 and 3?
416 is divisible by 2 but is not divisible by 3.
Is 3058 divisible by 6?
No. To be divisible by 6, a number must be even (divisible by 2) and divisible by 3. Although 3058 is even, it is not divisible by 3 since 3+0+5+8 = 16 which is not divisible by 3. Thus is it not divisible by 6.
