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Q: Is 9 plus 3u plus 5u plus 4v a product of four factors?

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9

3u - 5u= - 2u=====

-13 = 3u - 4 + 4 to both sides of equation to cancel it from the rigt hand side -9 = 3u divide trough by 3 (from 3u) U = 3

add 8 and 2 then take away 3. even u should get 7u.

T - U = 3T = 2U + 1(2U + 1) - U = 3U + 1 = 3U = 2T = 2U + 1 = 5The number is 52.

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7 + 4u = 70 - 3u[add 3u to both sides]7 + 4u + 3u = 70 - 3u + 3u7 + 7u = 70 + 07 + 7u = 707u = 70 - 77u = 63u = 9

9

7u.

49

Is 24u^2 + 35

u = 7

2u + 1 = 5u + 5 2u - 5u = 5 - 1 -3u = 4 3u = -4 u = -4/3

6u2+7u+53u-1

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