60 divided by 6 = 10
60 divided by 15 = 4
Yes, 1248 is divisible by 6. A number is divisible by 6 if it is divisible by both 2 and 3. Since 1248 is even (divisible by 2) and the sum of its digits (1 + 2 + 4 + 8 = 15) is divisible by 3, it meets both conditions. Therefore, 1248 is divisible by 6.
None of them. 15 is divisible by 3 and 5
Yes Example 1+5=6 and 6 is a multiple of 3
3, 9, 15, 21, 27, 33
Yes, it is. The digital root of 1430061, that is, the sum of all its digits is 1+4+3+0+0+6+1 = 15 The digital root of 15 is 1+5 = 6 which is divisible by 3. So 1430061 is divisible by 3.
If this is a T-F question, the answer is false. It is true that if a number is divisible by 6, it also divisible by 3. This is true because 6 is divisible by 3. However, the converse -- If a number is divisible by 3, it is divisible by 6, is false. A counterexample is 15. 15 is divisible by 3, but not by 6. It becomes clearer if you split the question into its two parts. A number is divisible by 6 if it is divisible by 3? False. It must also be divisible by 2. A number is divisible by 6 only if it is divisible by 3? True.
Multiples of 9 and 6 are also divisible by three, the reverse is not true. 15 is divisible by 3, but not 6 or 9. 27 is divisible by 3 and 9, but not 6. 12 is divisible by 3 and 6, but not 9. 54 is divisible by 3, 6 and 9.
Yes. 90 / 6 = 15
Yes, 1248 is divisible by 6. A number is divisible by 6 if it is divisible by both 2 and 3. Since 1248 is even (divisible by 2) and the sum of its digits (1 + 2 + 4 + 8 = 15) is divisible by 3, it meets both conditions. Therefore, 1248 is divisible by 6.
15
How can the following definition be written correctly as a biconditional statement? An odd integer is an integer that is not divisible by two. (A+ answer) An integer is odd if and only if it is not divisible by two
They are divisible by 2, 3, 4, 5, 6, 10, 12, 15, 30 and 60 at least.
To determine if 483 is divisible by 9, we can add the digits of 483 together: 4+8+3 = 15. Since 15 is not divisible by 9 (15 ÷ 9 = 1 with a remainder of 6), we can conclude that 483 is not divisible by 9. In general, a number is divisible by 9 if the sum of its digits is divisible by 9.
6 of them.
None of them. 15 is divisible by 3 and 5
No. But 870 is divisible by 3 (because 8+7+0 = 15 -> 1 + 5 = 6 and 6 is divisible by 3). 870/3 = 290.
105