Yes, that is correct.
Yes, 928 is divisible by two because it is an even number. A number is divisible by two if it can be divided evenly by 2 without leaving a remainder. In this case, 928 divided by 2 equals 464, which is a whole number without any remainder, confirming that 928 is indeed divisible by two.
Divide the number by thirteen. If the answer comes out even with no remainder, the number is divisible by thirteen.
The foolproof way is to divide 4 into it. If the answer is a whole number, it's divisible by 4. You can also tell by looking at it. If the last two digits are a multiple of 4, like 24 or 80, the whole number is divisible by 4.
No. Only even numbers are divisible by 2.
Take the number 3336. You know it's divisible by 1 because everything is. You know it's divisible by 2 because it's even. You know it's divisible by 3 because the digits add up to a multiple of 3 and you know it's divisible by 4 because the last two digits are divisible by 4. So you've found at least four factors: 1,2,3 and 4.
Only the whole numbers that end with a ' 0 ' are evenly divisible by 10.
The definition of an even number is a number that is divisible by 2. Thus ALL even numbers are evenly (sic) divisible by 2.
Any number evenly divisible by an even number is also even. A number evenly divisible by an odd number (such as 5) could be either even or odd.
Not evenly. It is an odd number and only even numbers evenly divisible by 2.
What whole number divisible by2 end with
A number is even if it is divisible by 2. It is doubly even if it is divisible by 4.
Any number evenly divisible by 2 is an even number
evenly divisible by 2
Yes. Any number that ends in 2, 4, 6, 8, or zero is evenly divisible by 2. If it's a whole number, then it's called an "even" number.
40 is an even number - it is divisible by 2 to produce a whole number
52 is evenly divisible by 2 therefore it is an even number.
As it is evenly divisible by 2, yes it is an even number.