None of the numbers in that range are divisible by 495. 495 is divisible by 3 and 5.
The foolproof way is to divide 4 into it. If the answer is a whole number, it's divisible by 4. You can also tell by looking at it. If the last two digits are a multiple of 4, like 24 or 80, the whole number is divisible by 4.
It is 83667.
How can the following definition be written correctly as a biconditional statement? An odd integer is an integer that is not divisible by two. (A+ answer) An integer is odd if and only if it is not divisible by two
There is no number, no matter the number of digits, that is only divisible by 2.
Any one of the infinitely many numbers of the form k*928 where k is an integer.
yes
1, 2, 4, 8, 16, 29, 32, 58, 116, 232, 464, 928
The multiples of 116 (which are infinite) are all divisible by 116 , including these: 116, 232, 348, 464, 580, 696, 812, 928, 1044 . . .
16 x 58 = 928.
928
A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.A number is divisible by 4 if the last two digits are divisible by 4.
928 =92800%
928/1
No, only multiples of two are divisible by two.
If the number is even then it is divisible by two, if it is odd it is not divisible by two
It is: 928 = CMXXVIII