Yes, 928 is divisible by two because it is an even number. A number is divisible by two if it can be divided evenly by 2 without leaving a remainder. In this case, 928 divided by 2 equals 464, which is a whole number without any remainder, confirming that 928 is indeed divisible by two.
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None of the numbers in that range are divisible by 495. 495 is divisible by 3 and 5.
The foolproof way is to divide 4 into it. If the answer is a whole number, it's divisible by 4. You can also tell by looking at it. If the last two digits are a multiple of 4, like 24 or 80, the whole number is divisible by 4.
It is 83667.
How can the following definition be written correctly as a biconditional statement? An odd integer is an integer that is not divisible by two. (A+ answer) An integer is odd if and only if it is not divisible by two
There is no number, no matter the number of digits, that is only divisible by 2.