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The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.

If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.

If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.

It gets a lot more complicated in the latter case if they can be non-integers.

The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.

If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.

If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.

It gets a lot more complicated in the latter case if they can be non-integers.

The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.

If ab represents a 2 digit number, so that, in fact, it is equivalent to 10*a+b, then it is divisible by 2 if b = 0, 2, 4, 6 or 8 and divisible by 5 if b is 0 or 5. The value of a makes no difference.

If ab represents the product of a and b and they are both integers, then ab is a multiple of 2 or 5 if at least one of a or b is a multiple or 2 or 5.

It gets a lot more complicated in the latter case if they can be non-integers.

The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.

It gets a lot more complicated in the latter case if they can be non-integers.

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The answer depends on whether ab represents a 2-digit number or, as in algebra, represents the product of a and b.

It gets a lot more complicated in the latter case if they can be non-integers.

Q: Is ab a multiple of 2 or 5 how do you know?

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25 is not a multiple of 5 - 5 is a multiple of 25. 25/5 is 5. So we know that the multiplication of 5 by 5 is 25. We also know 5 is a multiple of 25 because the square root of 25 is 5. Finally we know that 5 is a multiple of 25 because 5Â² is 25. Which is the inverse of the square root of 25.

LCM of (a) and (b) is given as (ab)/(GCF(a,b)) To find the GCF, factor and find common factors. 50 factors to [2 5 5] 80 factors to [2 2 2 2 5] Common factors are [2 5] = 10 50 * 80 / 10 = 400 ■

5 and 25*5*5*2*2*2(I know it's a long shot but there are only two differentnumbers)

== == 1) Draw a line segment AB of 5 units 2) Draw the perpendicular bisector CD of AB such that Cd meerts AB at C. 3) Mark off CE = 2 units on CD 4) Draw the straight line segments AE & BE. ABE is your triangle. Its base (AB) = 5 and height (CE) = 2, so its area = [base x ht] / 2 = 5 sq units

It is: (9+5)/2 and (8+2)/2 which is 7 and 5 Midpoint: (7, 5)

Related questions

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The least common multiple of 3 and 5 is 15. This, however is not a multiple of 2 so we must find the next common multiple of 3 and 5. This is 30. Since 30 is also a multiple of 2, 30 is therefore the least common multiple of 3, 5 and 2.

25 is not a multiple of 5 - 5 is a multiple of 25. 25/5 is 5. So we know that the multiplication of 5 by 5 is 25. We also know 5 is a multiple of 25 because the square root of 25 is 5. Finally we know that 5 is a multiple of 25 because 5Â² is 25. Which is the inverse of the square root of 25.

LCM of (a) and (b) is given as (ab)/(GCF(a,b)) To find the GCF, factor and find common factors. 50 factors to [2 5 5] 80 factors to [2 2 2 2 5] Common factors are [2 5] = 10 50 * 80 / 10 = 400 ■

5 and 25*5*5*2*2*2(I know it's a long shot but there are only two differentnumbers)

yes because if it has a zero or five at the end you know its a multiple of 5

Least Common Multiple (LCM) for 2 5 is 10

AB = 2 x 4 (8) C = 3 D = 5

Using the distance formula the length of ab is 5 units

== == 1) Draw a line segment AB of 5 units 2) Draw the perpendicular bisector CD of AB such that Cd meerts AB at C. 3) Mark off CE = 2 units on CD 4) Draw the straight line segments AE & BE. ABE is your triangle. Its base (AB) = 5 and height (CE) = 2, so its area = [base x ht] / 2 = 5 sq units

It is: (9+5)/2 and (8+2)/2 which is 7 and 5 Midpoint: (7, 5)

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