Using the distance formula the length of ab is 5 units
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
AB = 2 x 4 (8) C = 3 D = 5
AB/8Cas divided by 8/A can be reversed to multiplied by A/8so B/C x A/8 = AB/8CExample: If A=4 B=6 C=3then 6/3 divided by 8/4 = 2/2 = 1also AB/8C = 24/24 = 1Q.E.D.
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
End points: (-2, -4) and (-8, 4) Length of line AB: 10
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
AB = 2 x 4 (8) C = 3 D = 5
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
AB/8Cas divided by 8/A can be reversed to multiplied by A/8so B/C x A/8 = AB/8CExample: If A=4 B=6 C=3then 6/3 divided by 8/4 = 2/2 = 1also AB/8C = 24/24 = 1Q.E.D.
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It depends on the length. The surface area would be 4*length+8*length+16.
The perimeter decreases by 4. Decreasing the length by 4 decreases the perimeter by 8. Increasing the width by 2 increases the perimeter by 4. -8+4=-4 For example: Area of a rectangle could be: 8 x 6 (8 being the length and 6 being the width). The perimeter is 8+8+6+6=28 If the length is decreased by 4 then it becomes 4 If the width is increased by 2 then it becomes 8. The perimeter becomes 4+4+8+8=24
The length is 3*sqrt(5) = 6.7082, approx.