Using the distance formula the length of ab is 5 units
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
AB = 2 x 4 (8) C = 3 D = 5
AB/8Cas divided by 8/A can be reversed to multiplied by A/8so B/C x A/8 = AB/8CExample: If A=4 B=6 C=3then 6/3 divided by 8/4 = 2/2 = 1also AB/8C = 24/24 = 1Q.E.D.
End points: (-2, -4) and (-8, 4) Length of line AB: 10
Endpoints: A (-2, -4) and B (-8, 4) Length of AB: 10 units
Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
To find the length of segment AB, we can use the distance formula. Given points A (-1, 3) and B (11, -8), the length of AB is calculated as follows: [ AB = \sqrt{(11 - (-1))^2 + (-8 - 3)^2} = \sqrt{(11 + 1)^2 + (-11)^2} = \sqrt{12^2 + (-11)^2} = \sqrt{144 + 121} = \sqrt{265} \approx 16.28. ] Therefore, the length of AB is approximately 16.28 units.
AB = 2 x 4 (8) C = 3 D = 5
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
AB/8Cas divided by 8/A can be reversed to multiplied by A/8so B/C x A/8 = AB/8CExample: If A=4 B=6 C=3then 6/3 divided by 8/4 = 2/2 = 1also AB/8C = 24/24 = 1Q.E.D.
To find the length of segment AB, you simply add the lengths of segments AC and CB together. Since AC is 8 cm and CB is 6 cm, the length of AB is 8 cm + 6 cm = 14 cm. Therefore, segment AB is 14 cm long.
h
It depends on the length. The surface area would be 4*length+8*length+16.