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Q: Is the X Y or

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(y * x) - y = y * (x - 1)

(x2 - y2)/(x - y) = (x + y)(x - y)/(x - y) = x + y

y = sin(x+y) cos( x + y )[(1 + y')] = y' cos(x + y ) + y'cos(x + y ) = y' y'-y'cos( x+ y) = cos( x + y ) y'[1-cos(x+y)]= cos(x+y) y'= [cos(x+y)]/ [1-cos(x+y)]

1545(x-y)=3(x²-y²) (1545÷3)(x-y)=(x²-y²) 515(x-y)=(x²-y²) 515=(x²-y²)÷(x-y)

Given two numbers, x and y their difference is |x - y|. |x - y| = x - y if X â‰¥ y and |x - y| = y - x if x < y

X + Y (X + Y) ^2 = (X+Y)(X+Y) Factor = (X + Y)

There are two simple strategies to compare two numbers, X and Y: you can calculate X - Y. If X - Y > 0 then X > Y, if X - Y = 0 then X = Y and if X - Y <0 then X < Y. Or you can calculate X/Y. Provided both are greater than 0, if X/Y > 0 then X > Y if X/Y = 1 then X = Y if X/Y <1 then X < Y

Your question is like this:X+Y=15, X-Y=5, (X x Y)-X+Y= ?According to my calculations, X=10 and Y=5, therefore (X x Y)-X+Y= 45.

1. Calculate X % of Y X per cent of Y = X*Y/100 This implies that X% of Y is the same as Y% of X. 2. X and Y are given. What is X as a percentage of Y? X, as a percentage of Y = 100*X/Y

x^(4)*y*x^(5)*yMultiply x^(4) by y to get x^(4)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(4)y*x^(5)*yMultiply x^(4)y by x^(5) to get x^(9)y.(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y*yMultiply x^(9)y by y to get x^(9)y^(2).(d)/(dx) x^(4)*y*x^(5)*y=x^(9)y^(2)To find the derivative of x^(9)y^(2), multiply the base (x) by the exponent (9), then subtract 1 from the exponent.(d)/(dx) x^(4)*y*x^(5)*y=9x^(8)y^(2)The derivative of x^(4)*y*x^(5)*y is 9x^(8)y^(2).9x^(8)y^(2)

If y is a multiple of x, the LCM of x and y is y.

X=Y x ?

Commutative x + y = y + x x . y = y . x Associative x+(y+z) = (x+y)+z = x+y+z x.(y.z) = (x.y).z = x.y.z Distributive x.(y+z) = x.y + x.z (w+x)(y+z) = wy + xy + wz + xz x + xy = x x + x'y = x + y where, x & y & z are inputs.

x-y=x² only if y = x - x²

y=-x+4

It is x, y.

(x - y)(x + y)

Let x and y be two positive numbers. The cases are: x > y, then x - y > 0 x = y, then x - y = 0 x < y, then x - y < 0

So basically, when you stir a solution, it physically moves all of the chemicals around so the atoms of each are more evenly spread throughout the solution. imagine X represents one reactant, and Y represents the other reactant. Before stirring, they are mixed like this : X X X X X Y X Y X Y X Y Y Y Y Y After Stirring they are like this : X Y X Y X Y X Y X Y X Y X Y X Y X Y so more of the X molecules are next to more of the Y molecules so the reaction happens quicker.

x - y = -3 -y = -x - 3 y = x + 3 y-int. = 3 x-int. = -3

X + Y⁶X + Y * Y * Y * Y * Y * Y

Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps! Two integers (X & Y). X+Y=-3, X-Y=-11. x=-11+y --> (x)+y=-3 --> (-11+y)+y=-3 --> y=4 x=-11+4=-7 Hope that helps!

y = -x + 3 y - 3 = -x -y + 3 = x Therefore x = 3 - y

In expressions such as "x-y", both "x" and "y" can have any value. The value of "x-y" will depend on what the value of "x" and the value of "y" are.