If x is one of the numbers and y the other, then their sum is x+y = 53. So y = 53-x where x>0 and y>0 implying that x<53. Then, their product, P = x*y = x*(53-x) = 53*x - x2 for 0<x<53 [P is not defined for other values of x]
Scary I had the same math problem with my teacher Mr. Dates, the answer is -53/50. This was on Lesson 2-10 I believe try using my.hrw.com next time.
53 x 53 = 2809
53 itself. It is a prime number.
Expressed as a percentage, 53/53 x 100 = 100 percent.
If x is one of the numbers and y the other, then their sum is x+y = 53. So y = 53-x where x>0 and y>0 implying that x<53. Then, their product, P = x*y = x*(53-x) = 53*x - x2 for 0<x<53 [P is not defined for other values of x]
Scary I had the same math problem with my teacher Mr. Dates, the answer is -53/50. This was on Lesson 2-10 I believe try using my.hrw.com next time.
10% off of 53= 10% discount applied to 53= 53 - (10% * 53)= 53 - (0.10 * 53)= 53 - 5.3= 47.7
53% is a little over half. 53% of 100 is 53. 53% of 10 is 5.3. 53% of 200 is 106.
53 x 53 = 2809
56.18 100% of 53 = 53 6% of 53 = 0.06 x 53 = 3.18
1 and 53 are the factors of 53. 53 is a prime number, meaning only one and itself can be evenly divided into it.Factors of 53 are 53 & 1.
It is: -53/10 as an improper fraction
There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.There were 53 Wednesdays in 1952.
33 percent of 53 = 17.4933% of 53= 33% * 53= 0.33 * 53= 17.49
30% off of 53 = 37.1= 30% discount applied to 53= 53 - (30% * 53)= 53 - (0.30 * 53)= 53 - 15.9= 37.1
42:53 cannot be further simplified.It is 42:53 or 42/53.