x = { +6, -6 }
x = sq root of 36x = 6x = -6
The answer to the question depends on the set of numbers within which you are working. If you are working in integers, x2 = 2.25 has no solution. However, it does have a solution in rational numbers (x = 1.5). If working with rationals, x2 = 6 has no rational solution but it does have a solution in real numbers. Yet again, x2 = -6 has no solution in the reals, but does have a solution in complex numbers.
x = 6 or x = -6 This is because a negative multiplied by a negative gives a positive.
(x-6)(x+4) = 0 x = 6 or x = -4
x = { +6, -6 }
x2+x-6=0 * * * * * Perhaps the solution you are looking for is: x2 + x - 6 = (x - 2)(x + 3) = 0; whence, x = 2 or -3.
x = sq root of 36x = 6x = -6
X2 - X - 6 = 0what two factors of - 6 add up to - 1 ?(X + 2)(X - 3)============(- 2, 0 ) and (3, 0 )------------------------------solution set of points
The set is [ 16 ] .
The answer to the question depends on the set of numbers within which you are working. If you are working in integers, x2 = 2.25 has no solution. However, it does have a solution in rational numbers (x = 1.5). If working with rationals, x2 = 6 has no rational solution but it does have a solution in real numbers. Yet again, x2 = -6 has no solution in the reals, but does have a solution in complex numbers.
x = 6 or x = -6 This is because a negative multiplied by a negative gives a positive.
(x-6)(x+4) = 0 x = 6 or x = -4
n=6
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
x=14
Reading this as: 4x2-6=2x2 This implies that: -6=-2x2 3=x2 x=sqrt(3) and x=-sqrt(3) So x can equal plus or minus the square root of 3