x = { +6, -6 }
x = sq root of 36x = 6x = -6
x2≤64
x=18
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
x = { +6, -6 }
x = sq root of 36x = 6x = -6
x2≤64
if x2 + 7 = 37, then x2 = 29 and x = ±√29
x=18
x2-5x-36 = (x-9(x+4) when factored
x2 + 49 = 0 ∴ x2 = -49 ∴ x = 7i
-4 and 4
8
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
(x + 6)(x - 6)
the question is to solve (x^2-5x+5)^(x^2-36)=1