3
3
-2+5=3
(2x6 - 128) 2(x6 - 64) 2(x6 - 26 ) 2 (x3 - 23)(x3 + 23) x=2 ans The answer above is correct to 2(x6-26) 26√(x6-26) 2(x-6√2)3(x+6√2)3 2(x-1.1224620483093729814335330496792)3(x+1.1224620483093729814335330496792)3 Therefore, if that equation equals to 0, x=±1.1224620483093729814335330496792
If it is 2x9 = x6, then2x9 = x62x9 - x6= 0x6(2x3 - 1) = 0x6 = 0; x = 0 or2x3 - 1 = 0x3 = 1/2x = (1/2)1/3 = (4*1/2*4)1/3 = 41/3/2
-2 + 5 = xsame as:5 - 2 = xx = 3
The solutions are: x = -2 and y = 4
4x-7=24x=9 x=9/4
(3)(14) = 84x 42 =84X x=1/2
X= (3/5 , -2)
3x-1 = 7 3x = 8X= 8/3 = 2+2/3
x^2-6=0x^2=6 x=±√6