The combined area of all four walls is the height (h) times the perimeter (p) of the hall. Since the height is given as 11 m, we can calculate the perimeter...
p = 660 m2 ÷ 11 m = 60 m.
The perimeter is two times the length (l) plus two times the breadth (b).
p = 2l + 2b
The length is given as twice the breadth.
l = 2b
Substituting 2b for l in the previous equation gives us...
p = 2(2b) + 2b = 4b + 2b = 6b
We had determined that the perimeter is also 60 m, so...
6b = 60 m
Dividing each side of the equation by 6 gives us...
b = 10 m
Substituting 10 m for b in the equation for l above gives us...
l = 2(10 m) = 20 m
The area of the ceiling is...
a = l x b
Finally, substituting the values of l and b yields...
a = 20 m x 10 m = (20 x 10) x (m x m) = 200 m2
Of course, the last step in solving any word problem is to confirm that we found what was asked for (in this case, the area of the ceiling), which we did. Also, one advantage that word problems have over regular math problems is that they give us the benefit of what I call the ridiculous test. Ask yourself whether or not the magnitude and/or units of your answer is ridiculous for what was asked for (200 m2 is a reasonable ceiling area for a hall).
Area is length times width, perimeter is twice the sum of length and breadth.
2l+2w=48 l=2w 2(2w)+2w=48 4w+2w=48 6w=48 w=8 l=2*8=16 So, the length is 16 meters and the width (or breadth) is 8 meters.
2l+2w=24 l=2w 2(2w)+2w=24 4w+2w=24 6w=24 w=4 l=2w=2*4=8 Length is 8 meters, the width (or breadth) is 4 meters.
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.
Height
Area is length times width, perimeter is twice the sum of length and breadth.
10 x 5
Well, isn't that just a happy little problem to solve! To find the area of a rectangle, you multiply the length by the breadth. And to find the length, you can use the formula: length = (perimeter - 2 * breadth) / 2. Just remember, there are no mistakes, only happy accidents in math!
2l+2w=48 l=2w 2(2w)+2w=48 4w+2w=48 6w=48 w=8 l=2*8=16 So, the length is 16 meters and the width (or breadth) is 8 meters.
2l+2w=24 l=2w 2(2w)+2w=24 4w+2w=24 6w=24 w=4 l=2w=2*4=8 Length is 8 meters, the width (or breadth) is 4 meters.
If the only information that you have is ... A) the figure is a rectangle, and B) the perimeter ... then you cannot calculate the area. The area of a rectangle is the length multiplied by the height., The perimeter is twice the length plus twice the height. So, a rectangle with a length of 9 units and a height of 1 unit will have a perimeter of 20 units and an area of 9 square units. Another rectangle with a length of 6 units and a height of 4 units will also have a perimeter of 20 units, but it will have an area of 24 square units. To be able to calculate the area from the perimeter you need to know one of two additional things - either one of the measurements, or the ratio of the height to the length.+++To summarise, you can, IF you know the ratio as mentioned. Then apply that to half the perimeter to find the length and breadth.
when the length of the slab is more or equal to twice the breadth hence it has to be one way slab.
if you are given the circle's "height" then that is the diameter. the diameter is twice the length of the radius, so divide the height by two and you will get the radius.
2,058/2,058= remander if 0 times 3 with the 0 and that will give you 0 and then you try to find the height of the length? The Answer is Fourteen or 14 cm for the height The Answer is twenty-one or 21 for the length
If the only information that you have is ... A) the figure is a rectangle, and B) the perimeter ... then you cannot calculate the area. The area of a rectangle is the length multiplied by the height., The perimeter is twice the length plus twice the height. So, a rectangle with a length of 9 units and a height of 1 until will have a perimeter of 20 units and an area of 9 square units. Another rectangle with a length of 6 units and a height of 4 units will also have a perimeter of 20 units, but it will have an area of 24 square units. To be able to calculate the area from the perimeter you need to know one of two additional things - either one of the measurements, or the ratio of the height to the length.
For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.For a rectangle, calculate twice the length, plus twice the width.
Let the breadth = xSo, length = 2x+1Thus perimeter will be,2(2x+1+x)=122= 6x+2=122So, 6x=122-2=120So, x= 120/6=20Therefore length=2x+1=2(20)+1=41