a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
What is the 14th term in the arithmetic sequence in which the first is 100 and the common difference is -4? a14= a + 13d = 100 + 13(-4) = 48
It is a + 8d where a is the first term and d is the common difference.
35 minus 4 differences, ie 4 x 6 so first term is 11 and progression runs 11,17,23,29,35...
From any term after the first, subtract the preceding term.
You subtract any two adjacent numbers in the sequence. For example, in the sequence (1, 4, 7, 10, ...), you can subtract 4 - 1, or 7 - 4, or 10 - 7; in any case you will get 3, which is the common difference.
It is a*r^4 where a is the first term and r is the common ratio (the ratio between a term and the one before it).
chronological mean like first to fifth or in order , and sequence means a pattern
The common difference is 6; each number after the first equals the previous number minus 6.