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What is the first term of an arithmetic sequence with a common difference of 6 and a fifth term of 35?
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What is the fifth root of -243?
Fifth root of -243 is -3.
Mean median and mode are always equal?
The mean, median, and mode are not always equal. For example, consider the set of 5 values {2, 3, 5, 10, 10}. The arithmetic mean is 6. (The values sum to 30, and 30 divided by 5 is 6.) The median is 5. (The middle number of the 5 values, when sorted, is 5.) The mode is 10. (The value 10 appears most often in the set.) And, you probably didn't ask, but: The geometric mean is the fifth root of 3000, or about 4.96. The harmonic mean is 150 divided by 37, or about 4.05. The quadratic mean is the square root of 47.6, or about 6.9. Although the word "average" can technically be used to describe all of these values, in common parlance the word "average" refers to just the arithmetic mean.
What is the fifth root of fifteen equal to?
The fifth root of fifteen = 1.718772
How do you write 10 To The fifth power?
10 to the fifth power = 105
Four to the negative fifth power?
1024 * * * * * That is 4 to the fifth power. The question asked about the NEGATIVE fifth power. For the question that was asked, the answer is 1/1024
What is a number sequence where 24 is the fifth term in a sequence of 10 numbers?
To find the common difference in the arithmetic sequence, we can use the formula for the nth term of an arithmetic sequence: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. Given that 24 is the fifth term in a sequence of 10 numbers, we can set up the equation (24 = a_1 + 4d). We also know that there are 10 terms in the sequence, so the 10th term can be expressed as (a_{10} = a_1 + 9d). With this information, we can set up a system of equations to solve for the first term (a_1) and the common difference (d).
The first term is 4 and the common difference is 3. the fifth term of this sequence is?
The nth term of a arithmetic sequence is given by: a{n} = a{1} + (n - 1)d → a{5} = a{1} + (5 - 1) × 3 → a{5} = 4 + 4 × 3 = 16.
What is the fifth term of the arithmetic sequence 7 4 1?
As you are taking 3 away each time, the 5th term will be -5.
Can you explain a pattern in which 14 is the fifth term in a sequence of ten numbers?
It is not possible to explain because you have not specified the nature of the sequence. A sequence can be an arithmetic, or geometric progression, increasing or decreasing. Or it can be a polynomial or power progression, again increasing or decreasing. Or it can be a sequence of random numbers.
What is the nth term for 3 7 11 15?
The nth term for that arithmetic progression is 4n-1. Therefore the next term (the fifth) in the sequence would be (4x5)-1 = 19.
The first term of an arithmetic sequence 7 the tenth term is 34 what is the fifth term?
Some number x is added to 7 for every number in the sequence. So, the second number is 7+x, the third number is 7+2x... So the tenth number is 7+9x = 34. Solve for x, x=3. The fifth number is 7+4x, which is 7+(4*3), which is 19
What is the fifth term of the geometric sequence?
It is a*r^4 where a is the first term and r is the common ratio (the ratio between a term and the one before it).
What is the nth term of the sequence 2 4 6 8?
Ok, take the formula dn+(a-d) this is just when having a sequence with a common difference dn+(a-d) when d=common difference, a=the 1st term, n=the nth term - you have the sequence 2, 4, 6, 8... and you want to find the nth term therefore: dn+(a-d) 2n+(2-2) 2n Let's assume you want to find the 5th term (in this case, the following number in the sequence) 2(5) = 10 (so the fifth term is 10)
What is the meaning of fourth?
The one after "third" but before "fifth" in a sequence.
What is a pattern in which 23 is the fifth term in a sequence of ten numbers?
33332344444
What is the fifth term in a sequence of ten numbers?
your website is stupet im mad
How can you find the first term of an arithmetic sequence if you know the third and fifth terms?
Suppose A is the first term and R is common difference. Then, if t(n) is the nth term, t(n) = A + n*R Then t(5) = A + 5R and t(3) = A + 3R so that t(5) - t(3) = 2R Now t(1) = A + R = A + 3R - 2R (since R = 3R - 2R) So t(1) = t(3) - 2R You were given t(3) and have calculated 2R above, so can work out t(1).
