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What two consecutive even integer such that the smaller number is 5 times the larger number gives a sum of 34?

There can be no such integers: a smaller integer cannot be 5 times the larger number.


How do you add two integers if the have different signs?

You subtract the smaller from the larger and give the answer the sign of the number with the larger absolute value.


Is the sum of two integers positive or negative?

If for the two integers a + b = c, a is larger than zero and b is larger than the absolute value of the first number, then c is always positive. If a is smaller than zero, and b is larger than the absolute value of the second number, then c is positive. If a is smaller than zero, and b is smaller than the absolute value of the second number, then c is negative.


What number is smaller -11 or 5?

ANSWER: -11Negative integers are smaller than the positive integers.


Is -310 larger or smaller than -3100?

2790


How you determine a difference when subtracting two integers that have the same signs?

Ignore the signs and subtract the smaller number from the larger one.


How would you use a number line to put integers in order from greatest to least?

Smaller numbers always go to the left of larger number on the number line.


When the smaller of two consecutive integers is added to four times the larger the result is 59?

Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.


What is the rule for adding two integers that vary in sign?

Subtract the number with the smaller absolute value from the other. Give the answer the sign of the number with the larger absolute value.


If I divide a smaller number by a larger number will this indicate the percentage that the larger number is over the smaller number?

No, that will indicate the percentage the smaller number is of the larger number.


The product of 2 consecutive even integers is 48 what is the smaller number?

Smaller number is '6'


How many ways can a pair of integers be selected from the integers 1 to 99 so that the difference between them is 10?

If the order of the pairs of numbers doesn't matter (that is the pairs (1, 11) and (11, 1) are considered the same) then there are 89 such pairs.If the order does matter (that is the pairs (1, 11) and (11, 1) are considered different) then there are 178 such pairs.There must be one number larger than the other.The smaller number must be at least 1, so the larger number must be at least 11.The larger number must be at most 99, so the smaller number must be at most 89.Thus, looking at the smaller numbers, it can be one of the numbers 1 to 89 - a total of 89 possibilities - each of which has a corresponding larger number.Therefore there are 89 combinations of 2 integers from the number 1-99 that have a difference of 10.If however, the order of the integers is important, then the smaller number can be the first number or second number, which means that there are twice as many possible pairs, giving 178 permutations of 2 integers from the numbers 1-99 that have a difference of 10.