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Using the remainder formula for the Taylor polynomial approximation estimate the error in your approximation to sin n?
GilmarEnaje
If you use n terms from the Taylor expansion, the absolute value of the error is less than [|x|^(2n+1)]/(2n+1)!
If you use n terms from the Taylor expansion, the absolute value of the error is less than [|x|^(2n+1)]/(2n+1)!
If you use n terms from the Taylor expansion, the absolute value of the error is less than [|x|^(2n+1)]/(2n+1)!
If you use n terms from the Taylor expansion, the absolute value of the error is less than [|x|^(2n+1)]/(2n+1)!
Wiki User
∙ 9y ago
Wiki User
∙ 9y agoIf you use n terms from the Taylor expansion, the absolute value of the error is less than [|x|^(2n+1)]/(2n+1)!
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No.
Formula for finding zeros of polynomial function?
Try the quadratic formula. X = -b ± (sqrt(b^2-4ac)/2a)
Once you have reduced a polynomial to a cubic function you can always use the quadratic formula to finish the problem?
false
Once you have reduced a polynomial to a quartic function you can always use the quadratic formula to finish the problem?
false
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diameter = circumference/pi (pi = 3.14159265 or 3.14 for rough approximation).
What is the remainder thereom?
The remainder theorem states that if you divide a polynomial function by one of it's linier factors it's degree will be decreased by one. This theorem is often used to find the imaginary zeros of polynomial functions by reducing them to quadratics at which point they can be solved by using the quadratic formula.
Can you use the quadratic formula after reducing a polynomial to a quartic function?
No.
Formula for finding zeros of polynomial function?
Try the quadratic formula. X = -b ± (sqrt(b^2-4ac)/2a)
When a certain polynomial is divided by x - 3 its quotient is xsquared - 5x - 6 and its remainder is 5 What is the polynomial?
From the Division Algorithm for Polynomials theorem,f(x) = q(x)g(x) + r(x) or we say:dividend = (quotient)(divisor) + (remainder)In our case,quotient = x^2 - 5x - 6; divisor = x - 3; and remainder = 5.Substitute what you know into the formula, and you will have:f(x) = (x^2 - 5x - 6)(x - 3) + 5f(x) = x^3 - 5x^2 - 6x - 3x^2 + 15x + 18 + 5f(x) = x^3 - 5x^2 - 3x^2 - 6x + 15x + 18 + 5f(x) = x^3 - 8x^2 + 9x + 23 (this is the required polynomial)
Once you have reduced a polynomial to a quadratic function you can always use the quadratic formula to finish the problem?
True
Once you have reduced a polynomial to a cubic function you can always use the quadratic formula to finish the problem?
false
Once you have reduced a polynomial to a quartic function you can always use the quadratic formula to finish the problem?
false
What is LnCl2?
There is no element that corresponds to the abbreviation Ln. The closest approximation to this chemical formula is ZnCl2, or zinc chloride.
What is the formula for the diameter of a circle given the circumference?
diameter = circumference/pi (pi = 3.14159265 or 3.14 for rough approximation).
How do you convert thousands of an inch into millimeter?
If you mean for wire, the following link has both an exact formula, and a close approximation (with a simpler formula): http://en.wikipedia.org/wiki/American_wire_gauge#Formula
Why is .33 in the formula of volume for a cone?
It is 1/3, not 0.33 which is an approximation. The derivation of this formula requires knowledge of integration. For basic mathematical details follow the link below.
In general how would you factor the polynomial C2 - D2?
There is a formula for the difference of squares. In this case, the answer is (C + D)(C - D)
