99999999.99999
A $5000 investment at an annual simple interest rate of 4.4% earned as much interest after one year as another investment in an account that earned 5.5% annual simple interest. How much was invested at 5.5%?
Take the annual interest rate, divide it by 2 and multiply it by the amount you invested or borrowed.
Let P be the amount of invested money. Then, .08P = 336 P = 336/.08 = 4,200
Kate invested 4500.
Multiply the principal (P) by the annual* interest rate as a decimal (r) and the time in years* (t). *The time period may be expressed in months, etc. For example, $2000 invested at 7% simple interest for 5 years: I = Prt = 2000x0.07x5 = 140x5 = $700.
Two equations. x+y=56000 .07x=.05y Solve both of these equations simultaneously and it will be the answer. x+(.07/.05 x)=56000
It was eight years.
p = principal ie amount invested; r = annual rate of interest; t = time in years. interest receivable = (p x t x r)/100
Simple interest = 700*5/100*2 = 70Simple interest = 700*5/100*2 = 70Simple interest = 700*5/100*2 = 70Simple interest = 700*5/100*2 = 70
an investmntment of 4000 is made at an annual simple interest rate of 8%. How much additional money must be invested at 12% so that the total interest earned is 1640?
Simple interest = money invested x rate/100 x number of years
20, assuming annual compound interest, 24 if simple interest.