1117
342
24
49 & 81
3993
3332, 3333 and 3334 add up to 9999 - there are no three consecutive numbers that add up to 10,000.
(7777-6666)/1111 = 1 (4444+5555)/(9999/3333) = 3 8888/2222 = 4 4*3 + 1 =13
In order to find three different prime numbers that sum up to 40, we need to identify the possible combinations. The only prime number that is even is 2, so one of the prime numbers must be 2. The other two prime numbers that add up to 38 can be 19 and 17. Therefore, the sum of the three different prime numbers that add up to 40 is 2 + 19 + 17 = 38.
24
49 & 81
342
3993
30
0
1+2+3+4+5
If you want to add two numbers and get 775, there are 194 different ways to do it IF you onlyuse positive whole numbers ... a lot more than that if you're allowed to use negative numbersand fractions.If you want to add three numbers and get 775, there are even more ways to do it.
3332, 3333 and 3334 add up to 9999 - there are no three consecutive numbers that add up to 10,000.
To answer this question, you first need to find all the unique sets of 4 numbers that add up to 6. These are: 0006 0051 0042 0033 0411 0321 0222 3111 2211 Now we need to find which of these can be ordered to give numbers between 1111 and 9999: 0006: 6000 0051: 1500, 5001, 5010, 5100 0042: 2004, 2040, 2400, 4002, 4020, 4200 0033: 3003, 3030, 3300 0411: 1104, 1140, 1401, 1410, 4011, 4101, 4110 0321: 1203, 1230, 1302, 1320, 2013, 2031, 2103, 2130, 2301, 2310, 3012, 3021, 3102, 3120, 3201, 3210 0222: 2022, 2202, 2220 3111: 1113, 1131, 1311, 3111 2211: 1122, 1212, 1221, 2112, 2121, 2211 These are all the numbers between 1111 and 9999 with a digit sum of 6.