Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.
3
add all the numbers up and count how many numbers there are then divide it2+3+5+7=17 count the numbers. 4 17 divide by 4 = 4.25
assume dividing into whole number if you divide by 4 then remainder will be 0,1,2, or 3 by 6 then remainder will be 0,1,2,3,4 or 5 by 9 then remainder will be 0,1,2,3,4,5,6,7 or 8
3, 5, 11
5
10.
Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.
Say for example you have 16/5.In remainders, the answer would be 3r1. Now you have to divide the remainder by the divisor So for example: 1/5=0.2 Now you have to place the 3 from the answer we got from the remainder in front of the 0.2 answer: 3.2
105 can be divided evenly by 1, 3, 5, 7, 15, 21, 35, and 105. These are all the factors of 105, meaning they divide into 105 without leaving a remainder. Additionally, 105 can be divided by other numbers that are not factors, but those divisions will result in remainders.
prime numbers that divide into 1155 = 3, 5, 7, 11
One possibility is remainders after division by 5.
All non-negative numbers smaller than 9 ie 0, 1, 2, 3, 4, 5, 6, 7 and 8.
The Least Common Denominator (LCD) of 5 and 3 is 15. To find the LCD, you need to determine the smallest number that both 5 and 3 can divide into evenly. In this case, 15 is the smallest number that both 5 and 3 can divide into without any remainders.
20 / 4 = 5 (no remainder) 21 / 4 = 5 remainder 1 22 / 4 = 5 remainder 2 23 / 4 = 5 remainder 3 24 / 4 = 6 (no remainder) Therefore the numbers that can remain after you've divided a number by four are 0, 1, 2, and 3.
3
divide both numbers by their common factor (5). 15 divide by 5 is 3 25 divide by 5 is 5 So...... 3 over 5