4
In division by 5, you can have remainders of 0, 1, 2, 3, and 4. If you count zero, then you can have five possible remainders. If you are not counting zero, then 4 possible remainders.
12 13 19
Repeatedly divide by 5 (noting the remainders) until the quotient is zero. Then write the remainders out in reverse order.
10.
Any non-negative number smaller than 7.
The possible remainders are {0, 1, 2, 3, 4, 5, 6, 7} making eight of them.
assume dividing into whole number if you divide by 4 then remainder will be 0,1,2, or 3 by 6 then remainder will be 0,1,2,3,4 or 5 by 9 then remainder will be 0,1,2,3,4,5,6,7 or 8
There are 9 possible remainders: 0, 1, 2, 3, 4, 5, 6, 7, 8.
If the dividend is a multiple of 8 then there will be no remainders in the quotient otherwise the possible remainders are limitless
There are 8 possible remainders - including 0.
It is 5 because it is the highest number that will divide into 50 and 35 with no remainders