Oh honey, multiples of 5 up to 1000? Let me break it down for you. You've got 5, 10, 15, 20, and so on all the way up to 1000. It's like counting by fives on a hot summer day, simple as that. So, grab a glass of lemonade and start listing those multiples like it's nobody's business!
5 of them.
Since you didn't specify a single number, and all numbers are multiples of themselves, the five smallest multiples are the counting numbers 1 to 5.
The LCM of two consecutive numbers is their product. The LCM of two consecutive multiples of 5 is their product divided by 5. Two consecutive numbers cannot be multiples of 5.
99 of them.
All numbers do.
There are 199 multiples of 5 in that range. There are 128 multiples of 7 in that range. There are 28 numbers on both lists. 1000 - 299 = 701
5 of them.
the numbers go up in 5, making the Nth Term 5n.
There are 2000 4-digit numbers that are multiples of 5, so, instead of listing them all, it is equally valid to say: Any4-digit number whose final digit is either a 5 or a 0 is a multiple of 5. Get Right? :P
The first multiple of 3 is 3; the last multiple of 3 below 1000 is 999. (This can be determined by dividing 1000 by 3, ignoring the remainder, and then multiplying that number by 3 to determine the largest multiple of 3 less than 1000.) Since 999 is 3 times 333, there are 333 multiples of 3 that are less than 1000. So, consider them by pairs: 1st and 333rd = 3 + 999 = 1002 2nd and 332nd = (2 x 3) + (332 x 3) = 6 + 996 = 1002 3rd and 331st = (3 x 3) + (331 x 3) = 9 + 993 = 1002 up to 166th and 168th = (166 x 3) + (168 x 3) = 498 + 504 = 1002 167th = 501 (which is half of 1002) In other words, since 333 is not an even number, there are (333 - 1)/2 = 166 pairs, plus that extra half of a pair. The sum of all the multiples of 3 less than 1000 is 166.5 x 1002 = 166,833. The same can be done for the multiples of 5. The first multiple of 5 is 5; the last multiple of 5 below 1000 is 995. (This can be determined by dividing 1000 by 5, subtracting 1 since it divided evenly and you need the largest multiple less than 1000, and then multiplying that number by 5 to determine the largest multiple of 5 less than 1000.) Since 995 is 5 times 199, there are 199 multiples of 5 that are less than 1000. So, consider these by pairs as well.e are 1st and 199 = 5 + 995 = 1000 2nd and 198 = 10 + 990 = 1000 up to 100th = 500 (which is half of 1000) In other words, since 199 is not an even number, there are (199 - 1)/2 = 99 pairs, plus that extra half of a pair. So, the sum of all the multiples of 5 less than 1000 is 99.5 x 1000 = 99,500. If the desired answer is the sum of all numbers less than 1000 that are either multiples of 3 or 5, then the numbers that are multiples of both 3 and 5 have been included twice - once as multiples of 3 and again as multiples of 5. So, since all numbers that are both multiples of 3 and multiples of 5 are multiples of 15, determine the sum of all the multiples of 15 and subtract it from the sum of the multiples of 3 and the multiples of 5. We can repeat the same procedure again. The first multiple of 15 is 15; the last multiple of 15 less than 1000 is 990. Since 990 is 15 x 66, there are 66 multiples of 15 less than 1000. 1st and 66th = 15 + 990 = 1005 2nd and 65th = 30 + 975 = 1005 and so on Since 66 is an even number, there are 66/2 = 33 pairs. So the sum of all the multiples of 15 less than 1000 is 33 x 1005 = 33,165. The sum of all the multiples of 3 and all the multiples of 5, but not counting them twice, is 166,833 + 99,500 - 33,165 = 233,168.
Multiples of 50 are the only numbers that are both. All other multiples of 5 aren't.
The common multiples of 6 and 5 are 30, 60, 90, 120, 150, 180, and so on.
Multiples of 5.
There are eleven such numbers.Get the common multiple of those numbers. All other common multiples will be multiples of this common multiple; that is, you can multiply the common multiple by 1, by 2, by 3, etc. to get additional numbers that are multiples of both numbers.
All multiples of 5 are numbers ending in either 5 or 0.
Well, honey, I hate to break it to you, but the numbers 8 and 36 are not multiples of 5. Natural numbers are those positive integers starting from 1, and multiples of 5 are numbers that can be divided by 5 without any remainder. So, in this case, you're barking up the wrong tree.
There are three numbers between 10 and 50 which are divisible by both 3 and 5. All numbers that are multiples of 3 and 5 are the multiples of the lowest common multiples (lcm) of 3 and 5 which is 15. The multiples of 15 between 10 and 50 are {15, 30 and 45}, thus there are 3 numbers.