Let the sides be a b c and their opposite angles be A B C and so:-
Using the cosine rule angle A = 57.9 degrees
Using the cosine or sine rule angle B = 46.6 degrees
Angle C: 180-57.9-46.6 = 75.5 degrees
Area: 0.5*6*7*sin(75.5) = 20 square cm rounded
The angles, opposite these sides are 57.9, 46.6 and 75.5 degrees, respectively.
In order to comply with Pythagoras' theorem and the area of a triangle the dimensions are probably:- hypotenuse 12.5 cm, height 10 cm and base 7.5 cm
There are with infinitely many possible dimensions for triangles with a given area.
From the given dimensions no kind of triangle is possible.
The length of the hypotenuse is not sufficient information. You need the length of one of the legs or one of the acute angles. Or some other information that will enable you to derive that.
Using trigonometry the angles of the triangle are 56.09 degrees, 97.09 degrees and 26.81 degrees with an area of 22.82 square cm all rounded to two decimal places.
In order to comply with Pythagoras' theorem and the area of a triangle the dimensions are probably:- hypotenuse 12.5 cm, height 10 cm and base 7.5 cm
The height would be 4.8 cm.
Area is 16 having output of two dimensions
There are with infinitely many possible dimensions for triangles with a given area.
No.Additional Information:-Yes providing it's not an isosceles right angle triangle the possible dimensions are:- hypotenuse 8 cm, height 6.4 cm and base 4.8 cm because they comply with Pythagoras' theorem.So the area is:- 1/2*6.4*4.8 = 15.36 square cmNote that if it was an isosceles triangle then the dimensions and area could also be worked out that is why you should have specified in your question the type of triangle.
Using trigonometry the angles of the triangle are 98.4 degrees, 58.4 degrees, 25.2 degrees and with an area of 8.94 square cm
Using trigonometry the angles are 90 degrees, 59.5 degrees and 30.5 degrees with an area of 133.8896 square cm.
No because the given dimensions do not comply with Pythagoras; theorem for a right angle triangle.
Let the sides be abc and their opposite angles be ABC Angle C: (10^2 +11^2 -15^2)/(2*10*11) = 91.04179885 degrees Area: 0.5*10*11*sin(91.04179885) = 54.99090834 Area to the nearest integer = 55 square cm
From the given dimensions no kind of triangle is possible.
Let the sides of the triangle be abc and their opposite angles be ABC Angle C: (21^2 +20^2 -29^2)/(2*21*20) = 90 degrees by the cosine rule Area: 0.5*21*20*sin(90 degrees) = 210 square cm by the area sine rule Alternatively: 0.5*21*20 = 210 square cm because it is a right angle triangle
The length of the hypotenuse is not sufficient information. You need the length of one of the legs or one of the acute angles. Or some other information that will enable you to derive that.