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What is the area of a triangle having dimensions of 29 cm by 21 cm by 20 cm showing work?
Wiki User
∙ 7y ago
Let the sides of the triangle be abc and their opposite angles be ABC
Angle C: (21^2 +20^2 -29^2)/(2*21*20) = 90 degrees by the cosine rule
Area: 0.5*21*20*sin(90 degrees) = 210 square cm by the area sine rule
Alternatively: 0.5*21*20 = 210 square cm because it is a right angle triangle
Wiki User
∙ 7y ago
Wiki User
∙ 7y agoIf you know the three side lengths of a triangle, you an use Heron's formula to calculate the area.
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HELP PLS The dimensions of triangle A are twice the dimensions of triangle B. The area of triangle B is 8 cm2. What is the area of triangle A Options :64 cm216 cm232 cm250 cm2?
Sorry the options are actually 64 cm2, 16 cm2, 32 cm2, 50 cm2. Thanks
