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What are the dimensions of a rectangle that has a perimeter of 29 cm and an area of 50.3125 square cm?
Wiki User
∙ 7y ago
Let the dimensions be x and y:-
If: 2x+2y = 29 then y =14.5-x
If: xy = 50.3125 then x(14.5-x) = 50.3125
Expanding brackets and transposing terms: 14.5x -x^2 -50.3125 = 0
Using the quadratic equation formula: x = 8.75 or x = 5.75
Therefore dimensions of the rectangle are: length = 8.75 cm and width = 5.75 cm
Check: 2(8.75+5.75) = 29 cm
Check: 8.75*5.75 = 50.3125 square cm
Wiki User
∙ 7y ago
Wiki User
∙ 7y agoYou need to write two equations, one for the perimeter, and one for the area, then solve. These are the equations:l w = area
2(l+w) = perimeter
Replace the known area and perimeter, then solve the equations.
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