even numbers 1-100
101
Every second number is Even. So there are 50 even numbers from 1 to 100 if you include 100. If you do not include 100 in the count there are obviously 49. The wording of the question is not clear on whether 100 is to be included or not.
There are 25 such numbers.
The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
even numbers 1-100
In Java:System.out.println("Even numbers")for (int i = 2; i
50
101
There are 100 even numbers between 1 and 200 (inclusive).
101
The only even prime number (not only from 1 to 100, but in general) is 2. All other even numbers are multiples of 2, and therefore, by definition, not prime numbers.
Every second number is Even. So there are 50 even numbers from 1 to 100 if you include 100. If you do not include 100 in the count there are obviously 49. The wording of the question is not clear on whether 100 is to be included or not.
Every number has 1 as a multiple. 1*100 = 100 1*7 = 7 As 1 is an odd number there are no numbers with only even multiples.
n*(n+1)=sum 100*(100+1)=10100
Since odd numbers are in a ratio of 1:2 it means for every one odd there will be one even, there would be 50 odd numbers between 1-100, and 50 even numbers. So 50%.
There are 25 such numbers.