The given vertices when plotted on the Cartesian plane forms a rectangle with diagonals of square root of 50 in lengths and they both intersect at (3.5, 4.5)
The diagonals are of length sqrt(50) = 7.071 units and they intersect at (3.5, 4.5).
No because the diagonals of a parallelogram are of different lengths
When the given vertices are plotted and joined together on the Cartesian plane they will form a 4 sided quadrilateral whose diagonals intercept each other at right angles and so multiplying the lengths of the diagonals divided by two will produce an area of 80 square units.
A parallelogram with sides whose lengths are half the diagonals of the original quadrilateral.
The answer depends on the shape of the quadrilateral and the form in which that information is given: for example, lengths of sides and angles, coordinates of vertices.
No because a kite is a 4 sided quadrilateral with two diagonals of different lengths that intersect each other at right angles.
No because the diagonals of a parallelogram are of different lengths
When the given vertices are plotted and joined together on the Cartesian plane they will form a 4 sided quadrilateral whose diagonals intercept each other at right angles and so multiplying the lengths of the diagonals divided by two will produce an area of 80 square units.
A parallelogram with sides whose lengths are half the diagonals of the original quadrilateral.
diagonals
The answer depends on the shape of the quadrilateral and the form in which that information is given: for example, lengths of sides and angles, coordinates of vertices.
No because a kite is a 4 sided quadrilateral with two diagonals of different lengths that intersect each other at right angles.
In geometry, a cyclic quadrilateral is a quadrilateral whose vertices all lie on a single circle. The vertices are said to be concyclic. In a cyclic quadrilateral, opposite angles are supplementary (their sum is π radians or 180°). Equivalently, each exterior angle is equal to the opposite interior angle. The area of a cyclic quadrilateral is given by Brahmagupta's formula as long as the sides are given. This area is maximal among all quadrilaterals having the same side lengths. Ptolemy's theorem expresses the product of the lengths of the two diagonals of a cyclic quadrilateral as equal to the sum of the products of opposite sides. In any convex quadrilateral, the two diagonals together partition the quadrilateral into four triangles; in a cyclic quadrilateral, opposite pairs of these four triangles are similar to each other. Any square, rectangle, or isosceles trapezoid is cyclic. A kite is cyclic if and only if it has two right angles. ----Wikipedia
A quadrilateral has four sides with lengths, two diagonals with lengths, four inside angles, four outside angles, and an area. The angles are the only things you can measure with a protractor.
Using the cosine formula in trigonometry the diagonals of the quadrilateral works out as 5.71cm and 6.08cm both rounded to two decimal places
The lengths of the diagonals work out as 12 cm and 16 cm
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
Yes the diagonals of a rectangle are equal in lengths