-199
25%
Every number has 1 as a factor.
All numbers have an infinite amount of multiples.
prime numbers can only be multiples of 1 and itself. perhaps 3 is just the number you want.
Since you didn't specify a single number, and all numbers are multiples of themselves, the five smallest multiples are the counting numbers 1 to 5.
25%
Multiples of 1- 1, 2 3, 4 ,5, 6, 7, 8, 9, 10-- Like counting Multiples of 2- 2,4,6,8,10,12, ect. Multiples of 3- 3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,51,54, Multiples of 4- Multiples of 5- Multiples of 6
99 of them. Each and every one of the numbers between 100 and 200 is a multiple of itself and 1.
All integers from 1 to 200.
200 and 300 are multiples of 100, among many others.
All of the counting numbers are multiples of ' 1 '.
Write out the numbers 1 to 200 in 20 rows. Cross out 1. Start at 2 and cross out multiples of 2. That would eliminate all the rest of the even numbers. Go to the next uncrossed-out number (3) and cross out all of its multiples. Some of them will already be crossed out. You can stop by the time you get to 15. All of the uncrossed-out numbers are prime.
3. All other multiples of 3 are not prime.
All of those numbers have an infinite number of multiples.
All of those numbers have an infinite amount of multiples.
i don't know that's why i came on wikianswers
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