Any set of numbers that you choose can be the next number. It is easy to find a rule based on a polynomial of order 6 such that the first six numbers are as listed in the question followed by your chosen next number. A polynomial of order 9 will fit the above six and any three following numbers. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest solution here, besed on a polynomial of order 5 is:
U(n) = (221*n^5 - 3845*n^4 + 24725*n^3 - 72055*n^2 + 94994*n - 41760)/120 for n = 1, 2, 3, ...
and, accordingly,
U(7) = 464,
U(8) = 2154 and
U(9) = 6867.
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Any three number that you choose can be the next three numbers. It is easy to find a rule based on a polynomial of order 9 such that the first six numbers are as listed in the question followed by the chosen three numbers. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.
The simplest polynomial solution is
U(n) = (221*n^5 - 3845*n^4 + 24725*n^3 - 72055*n^2 + 94994*n - 41760)/120 for n = 1, 2, 3, ...and, accordingly, the next three numbers are: 464, 2154 and 6867. Check it out!
Three consecutive numbers whose sum is 84 are 27, 28 and 29 AND 26, 28 and 30.
2*2*7 = 28
28
To find the mean of a set of numbers, you add up all the numbers and then divide the sum by the total count of numbers. Therefore, the mean of 19, 20, 24, 28, and 29 is (19 + 20 + 24 + 28 + 29) / 5 = 24.
2,3 and 28