Q: What are the odds that you will get tails only once in three coin tosses?

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The odds of each coin toss are 50-50. The coin has no memory; there is no record of what the last four tosses are. EVERY toss is at 50-50 odds.

3 to 1

The odds that a tossed coin will land tails side down remain one in two no matter how many times the coin has previously been tossed.

Three in eight are the odds of getting exactly two heads in three coin flips. There are eight ways the three flips can end up, and you can get two heads and a tail, a head and a tail and a head, or a tail and two heads to get exactly two heads.

The probability of the coin landing "head" side up is 50/50, meaning it could land "head" side up or "tail" side up. The odds of any single coin flip are always the same, no matter what happened on the previous tosses -- provided the coin is not a "double-head" (or "double-tail") "trick" coin

Related questions

The odds of each coin toss are 50-50. The coin has no memory; there is no record of what the last four tosses are. EVERY toss is at 50-50 odds.

3 to 1

Assuming a fair coin, the odds of getting four tails in a row are 1 in 16.

The odds that a tossed coin will land tails side down remain one in two no matter how many times the coin has previously been tossed.

>>> 1:7 (or, if you like probability, 87.5%)I disagree. There are four possible combinations of three tosses (where order does not matter):HHHHHTHTTTTTThree of these combinations will show at least one head - only by throwing three tails will you not throw at least one head.Thus, the probability of throwing at least one head in three flips is 75%.

If the coin is fair, thenThe chance of tails on the 1st toss is 50% (1/2).The chance of tails on the 2nd toss is 50% (1/2).The chance of tails on the 3rd toss is 50% (1/2).The chance of tails on the 4th toss is 50% (1/2).The chance of tails on the 5th toss is 50% (1/2).The chance of tails on the 6th toss is 50% (1/2).The probability of getting all of them is (1/2) x (1/2) x (1/2) x (1/2) x (1/2) x (1/2) = 1/64 = 1.5625 % .The odds are 63 to 1 against.

The answer I'm editing says the odds are 1 in 8. This is true only if you actually mean the probability of getting 3 tails in a row, rather than just 3 of either heads or tails in a row. In mentioned case, the first flip doesn't matter which side it lands on, just the proceeding two flips do. So, the odds of flipping a coin three times with the same outcome are 1 in 2^2 or 1 in 4. The odds of flipping three tails in a row are 1 in 2^3 or 1 in 8.

the only combination which does not produce heads at least once it tails twice. the odds of getting tails twice is 0.5*0.5=0.25 so the odds for getting heads at least once is 1-0.25=0.75 or 75% or 3/4.

lets get some facts odds of head on 1 coin 50% or evens odds of no head 50% or evens the possible results vary from 1 coin to 2 coins. 1 coin has 2 results heads or tails 2 coins have 4 results. heads heads, tails tails, tails heads, heads tails. each outcome has a probability of 25%. for the question we remove the heads and tail probability and we have 2 outcomes with heads and one without. so 2 to 1 chance or 33.3333 recuring chance.

The odds in this case are not relevant. The odds for choosing N32 are same as any other letter-number combination. Just like trying to figure out a flip of a coin if it's going to head or tails. The odds on each flip are 50/50. The coin has no memory.

Saying that the odds of something occurring are a to b (or a:b) means that we expect the event to occur a times for every b times it does not occur. For instance, the odds of drawing tails on a coin flip are 1 to 1, so if we repeat the experiment a very large number of times, we will have 1 occurrence of "tails" for every occurrence of "heads". The odds of getting a 5 on a dice roll are 1:5, and so on.

There are 4 possible outcomes, HH, HT, TH, TT. If we assume the odds of tossing heads or tails on any toss is 1/2 (50:50) the odds of tossing heads twice in a row is 1/4 (or 25%).