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What are the points of contact when the line x equals 2 -2y crosses the curve x2 plus 4y2 equals 4?
Wiki User
∙ 6y ago
Equations: x = 2 -2y and x^2 +4y^2 = 4
If: x = 2 -2y
Then: x^2 = 4y^2 -8y +4
If: x^2 +4y^2 = 4
Then: 4y^2 -8y +4 +4y^2 = 4
Collecting and transposing terms: 8y^2 -8y = 0 or y^2 -y = 0
Factorizing the above: (y-1)(y+0) = 0 meaning y = 1 or 0
By substitution points of contact are made at: (0, 1) and (2, 0)
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoThey are (0, 1) and (2, 0).
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Where are the points of contact when the line 2x plus 5 equals 4 crosses the curve y squared equals x plus 4 on the Cartesian plane?
The two solutions are (x, y) = (-0.5, -sqrt(3.5)) and (-0.5, sqrt(3.5))
What are the points of contact that the curve of y equals x squared -x -12 makes with the x and y axes on the Cartesian plane?
If: y = x2-x-12 Then points of contact are at: (0, -12), (4, 0) and (-3, 0)
Where are the points of contact when the line 3x -y equals 5 passes through the curve 2x squared plus y squared equals 129?
It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)
What is the difference between tangent and secant line?
The tangent line is the instantaneous rate of change at a point on a curve. The secant line crosses a curve twice at points A and B, representing the average rate of change between those two points.
Where do you find the solutions to a quadratic equation on a graph?
The solutions to a quadratic equation on a graph are the two points that cross the x-axis. NB A graphed quadratic equ'n produces a parabolic curve. If the curve crosses the x-axis in two different points it has two solution. If the quadratic curve just touches the x-axis , there is only ONE solution. It the quadratic curve does NOT touch the x-axis , then there are NO solutions. NNB In a quadratic equation, if the 'x^(2)' value is positive, then it produces a 'bowl' shaped curve. Conversely, if the 'x^(2)' value is negative, then it produces a 'umbrella' shaped curve.
Where are the points of contact when the line 2x plus 5 equals 4 crosses the curve y squared equals x plus 4 on the Cartesian plane?
The two solutions are (x, y) = (-0.5, -sqrt(3.5)) and (-0.5, sqrt(3.5))
What are the points of contact when the curve y equals x2 -x -12 cuts through the y and x axes on the Cartesian plane?
14
What are the points of contact that the curve of y equals x squared -x -12 makes with the x and y axes on the Cartesian plane?
If: y = x2-x-12 Then points of contact are at: (0, -12), (4, 0) and (-3, 0)
Where are the points of contact when the line 3x -y equals 5 passes through the curve 2x squared plus y squared equals 129?
It works out that line 3x-y = 5 makes contact with the curve 2x^2 +y^2 = 129 at (52/11, 101/11) and (-2, -11)
What are the points of contact when the line 2x plus 5y equals 4 transverses the curve y squared equals x plus 4?
If 2x+5y = 4 and y^2 = x+4 then by combining the equations into a single quadratic equation and solving it the points of contact are made at (12, -4) and (-7/2, 3/2)
What is the difference between tangent and secant line?
The tangent line is the instantaneous rate of change at a point on a curve. The secant line crosses a curve twice at points A and B, representing the average rate of change between those two points.
What are the points of contact between the line 3x -2y equals 1 and the curve 3x squared -2y squared plus 5 equals 0?
Equations: 3x-2y = 1 and 3x^2 -2y^2 +5 = 0 By combining the equations into one single quadratic equation and solving it the points of contact are made at (3, 4) and (-1, -2)
What is the value of c when y equals x plus c is a tangent to the curve y equals 3 -x -5x squared hence finding the point of contact of the line with the curve showing work?
-2
Where do you find the solutions to a quadratic equation on a graph?
The solutions to a quadratic equation on a graph are the two points that cross the x-axis. NB A graphed quadratic equ'n produces a parabolic curve. If the curve crosses the x-axis in two different points it has two solution. If the quadratic curve just touches the x-axis , there is only ONE solution. It the quadratic curve does NOT touch the x-axis , then there are NO solutions. NNB In a quadratic equation, if the 'x^(2)' value is positive, then it produces a 'bowl' shaped curve. Conversely, if the 'x^(2)' value is negative, then it produces a 'umbrella' shaped curve.
What is the value of k when y equals 3x plus 1 is a line tangent to the curve of x squared plus y squared equals k hence finding the point of contact of the line to the curve?
It is (-0.3, 0.1)
How would you go about determining the area under the curve so that you avoid the cancelling out nature of the area above the x-Axis with the area below the x-Axis?
Find the roots of the equation that defines the curve. these are the points where the curve crosses the x-axis.Then integrate between the first end-point and first root, first and second root, etc until the last root and the second end-point. Add together the absolute values of the integrals.Find the roots of the equation that defines the curve. these are the points where the curve crosses the x-axis.Then integrate between the first end-point and first root, first and second root, etc until the last root and the second end-point. Add together the absolute values of the integrals.Find the roots of the equation that defines the curve. these are the points where the curve crosses the x-axis.Then integrate between the first end-point and first root, first and second root, etc until the last root and the second end-point. Add together the absolute values of the integrals.Find the roots of the equation that defines the curve. these are the points where the curve crosses the x-axis.Then integrate between the first end-point and first root, first and second root, etc until the last root and the second end-point. Add together the absolute values of the integrals.
When was Points on the Curve created?
Points on the Curve was created on 1984-01-16.
