It is difficult to be sure because the browser used for posting questions is pretty much useless and strip out most mathematical symbols. Having made that clear, the answer is probably 0, 3 and -5.
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I guess your function was: q(x) = x(x - 3)(x + 5)
The zeros are when x = 0, 3 or -5.
3X = x2 - 2xsubtract 3X from each sideX2 - 5X = 0factor out an XX(X - 5) = 0=========X = 0--------orX = 5--------
NOTE: xx can be written as x^2 i.e. x squared 3x^2 + 16x + 5 = 3 x^2 + x + 15x + 5 (Since 16x = x + 15x) = x ( 3x + 1 ) + 5 ( 3x + 1 ) = ( x + 5 ) ( 3x + 1 ) Therefore the factors are ( x + 5 ) and ( 3x + 1 )
8-3x=238-8-3x=23-8 subtract 8 from both sides-3x=15-3x/-3 = 15/-3 divide both sides by -3 to solve for xx = -5
3x-5=3x+5 There is no solution.
Subtract 5 from each side: 16 = 5x + 3x ie 16 = 8xDivide each side by 8: 2 = x21 = 5x + 3x + 521 - 5 = 8x16 = 8x16/2 = x2 = xx = 2Check:21 = 5(2) + 3(2) + 521 = 10 + 6 + 521 = 21