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What coefficient would the O2 have after balancing C4H8 O2-CO2 H2O?
the answers is 6 _apex
What is the coefficient of carbon dioxide after balancing the following equation khco3 s k2co3 s h2o g co2 g?
The balanced equation is 2KHCO3(s) → K2CO3(s) + H2O(g) + CO2(g). The coefficient of carbon dioxide (CO2) in the balanced equation is 1.
How do you balance C6H14 O2 yield CO2 H2O?
To balance the equation C6H14 + O2 -> CO2 + H2O, start by balancing the carbon atoms. This requires putting a coefficient of 6 in front of CO2. Next, balance the hydrogen atoms by adding a coefficient of 7 in front of H2O. Finally, balance the oxygen atoms by adjusting the coefficient in front of O2, which in this case is 9.
What is the balanced reaction of propane c3h8?
If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
Try balancing the equations for the reactions in which propane (C3H8) and butane (C4H10) are burned in oxygen to form carbon dioxide and water.?
Burning of propane:CH3H8 + 5 O2 = 3 CO2 + H2OBurning of butane:2 CH4H10 + 13 O2 = 8 CO2 + 10 H2O
What coefficient would the O2 have after balancing C3H8 plus O2 CO2 plus H20?
5
What coefficient would O2 have after balancing C3H8 O2 CO2 H2O?
C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5
What coefficient would the O2 have after balancing C4H8 O2-CO2 H2O?
the answers is 6 _apex
How many grams of CO2 will be produced by burning 34.3 gram of C3H8?
To calculate the amount of CO2 produced when burning 34.3 grams of C3H8 (propane), you need to balance the chemical equation for the combustion of C3H8. Since each mole of C3H8 produces 3 moles of CO2, you first convert 34.3 grams of C3H8 to moles, calculate the moles of CO2 produced, and then convert that to grams of CO2.
If 100.0g C3H8 is burned completely how many grams CO2 would be produced if the only source of carbon is C3H8?
The reaction isC3H8 + 5O2 ----> 3CO2 + 4H2O100g of propane is approx 2.27 moles.From the equation above, we see that the ratio of C3H8 to CO2 is 1:3, therefore the number of moles of CO2 which form is approx 6.82.This relates to a mass of 300g of CO2
What is the coefficient C3H8 O2 CO2 H2O?
2c4h10 + 13o2 => 8co2 + 10h2o (I am having some trouble with my typography today, but all those letters above should be capitalized.)
How many grams of CO2 will be produced by burning 22 gram of C3H8?
To calculate the grams of CO2 produced by burning 22 grams of C3H8, first determine the moles of C3H8 using its molar mass, then use the balanced chemical equation for the combustion of C3H8 to find the moles of CO2 produced, and finally convert moles of CO2 to grams using the molar mass of CO2.
When 2.13 moles of C3H8 burn in excess oxygen how many moles of CO2 will be formed assuming complete combustion?
Out of one mole C3H8 three moles carbondioxide (CO2) are formed by complete combustion of it.So 2.13 mole C3H8 make 3*2.13 mole CO2 = 6.39 moleCO2
What is the coefficient of carbon dioxide after balancing the following equation khco3 s k2co3 s h2o g co2 g?
The balanced equation is 2KHCO3(s) → K2CO3(s) + H2O(g) + CO2(g). The coefficient of carbon dioxide (CO2) in the balanced equation is 1.
How do you balance c3h8 plus o2 equals co2 plus H2O?
C3h8 + 5o2 -> 3co2 + 4h2o
How do you balance C6H14 O2 yield CO2 H2O?
To balance the equation C6H14 + O2 -> CO2 + H2O, start by balancing the carbon atoms. This requires putting a coefficient of 6 in front of CO2. Next, balance the hydrogen atoms by adding a coefficient of 7 in front of H2O. Finally, balance the oxygen atoms by adjusting the coefficient in front of O2, which in this case is 9.
What is the balanced reaction of propane c3h8?
If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O
