You move the graph upwards by 2 units.
y=x+1 there for answer is 2
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.
On my graphing calculator, a TI84 Plus, I can enter the equation into the Y= (a button) and then graph it by hitting the Graph button.
It is translated left 8 and up 4.
3
y=x+1 there for answer is 2
y equals x-4 plus 2 is the same as y = x-2. You just translate the graph of y=x, 2 units to the right, OR 2 down.
First, reflect the graph of y = x² in the x-axis (line y = 0) to obtain the graph of y = -x²; then second, shift it 3 units up to obtain the graph of y = -x² + 3.
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The lines are parallel.
The equation you have given, y + 2 = 7, does not describe a line, it describes the number 5. You would not graph a single number, there is nothing to graph.
So, if we see the basic equation y=mx+b, we see that m=2, and b=1. If you look closely, this is basic rotation and translation of the original graph. First, I would translate the "mother graph" (y=mx) and then translate one up. Then, we would rotate the graph to the right two units.
A straight line, passing through the point (0,5) with a gradient of -3.
x2 + y - 49 = 0y = -x2 + 49First, plot the graph of y = -x2, with a vertex (0, 0), then translate it 49 units up. The vertex becomes (0, 49), which is a maximum point (the parabola opens downward).Or make a table to obtain several corresponding y-values for x = -3, -2, -1, 0, 1, 2, 3. Plot the points (x, y), and draw the graph of y = -x + 49.
If you were to graph both equations side by side, you would see that they are parallel lines. Both equations have the same slope it is just that the line would be moved down in the graph because of the intercept change.
You can do the equation Y 2x plus 3 on a graph. On this graph the Y would equal 5 and X would equal to 0.