To determine what digit to add to 13678 to make it divisible by 4, we need to look at the last two digits, which are 78. A number is divisible by 4 if the number formed by its last two digits is divisible by 4. Since 78 divided by 4 gives a remainder of 2, we can add 2 to 78 to get 80, which is divisible by 4. Therefore, adding the digit 2 to the end of 13678 makes it 136782, which is divisible by 4.
To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.
no
Any number whose last digit is 0 would be divisible by both these numbers. 1000, 1010, 1020...
Not evenly. You get 43.2 as the answer. To be divisible by 10, the last digit must be 0 The last digit of 432 is 2 which is not 0, so it is not divisible by 10.
No, 1017 is not divisible by 5. A number is divisible by 5 only if its last digit is 0 or 5. Since the last digit of 1017 is 7, it is not divisible by 5
To be divisible by 5, the last digit must be 0 or 5. The last digit of 305 is 5, so it is divisible by 5.
If the last digit is 0 or 5 then the number is divisible by 5. Last digit of 745 is 5 so, 745 is divisible by 5.
no
Any number whose last digit is 0 would be divisible by both these numbers. 1000, 1010, 1020...
Not evenly if you look at the last number and it is an even number such as 2,4,6,8 then it would be evenly divisible by 2.
Not evenly. You get 43.2 as the answer. To be divisible by 10, the last digit must be 0 The last digit of 432 is 2 which is not 0, so it is not divisible by 10.
No, 1017 is not divisible by 5. A number is divisible by 5 only if its last digit is 0 or 5. Since the last digit of 1017 is 7, it is not divisible by 5
To be divisible by 5, the last digit must be 0 or 5. The last digit of 28 is neither 0 nor 5, so it is not divisible by 5.
Yes, 450 is divisible by 5. A number is divisible by 5 if its last digit is 0 or 5. In this case, the last digit of 450 is 0, so it is divisible by 5.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 195 is a 5 which is NOT a 0, so 195 is NOT divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 312 is a 2 which is NOT a 0, so 312 is NOT divisible by 10.
All multiples of 10 end in a zero To be divisible by 10, the last digit must by a 0 The last digit of 926 is a 6 which is NOT a 0, so 936 is NOT divisible by 10.