0
Best Answer
We cannot answer since you didn't give any numbers at all to solve this with.
Wiki User
∙ 6y agoThis answer is:
More answers
Wiki User
∙ 6y agoX=y+k
This answer is:
Add your answer:
Earn +20 ptsQ: What does K plus Y equals?
Write your answer...
Submit
Still have questions?
Related questions
What is the value of k when y equals 3x plus 1 and is a line tangent to the curve of x squared plus y squared equals k?
k = 0.1
What are the possible value of k when the line y equals x plus k is a tangent to the circle x squared plus y squared equals 25?
They are +/- 5*sqrt(2)
What is the value of k when y equals 3x plus 1 is a line tangent to the curve of x squared plus y squared equals k hence finding the point of contact of the line to the curve?
It is (-0.3, 0.1)
Fx equals 3 plus 4x?
y = 3x + 2x^2 + k where k is any number
What is y plus y plus y plus y equals?
4y
What is the value of k when the straight y equals 3x-1 is a tangent to the curve x squared plus y squared equals k?
2
What is k equals xy for x?
k = x y x = k/y
What are the possible values of k if the line y equals 2x plus k with the curve of y equals x squared -2x -7 at 2 distintive points or at only 1 point?
It works out that k must be greater than -11 or k must equal -11
If 3 plus y equals a 3-y equals a then a equals y equals?
a = 3 and y = 0
What is the value of k when the line y equals 3x plus 1 is a tangent to the curve of y2 plus x2 equals k?
If: y = 3x +1 then y^2 = 9x^2 +6x +1 If: y^2 +x^2 = k then y^2 = k -x^2 So: 9x^2 +6x +1 = k -x^2 Transposing terms: 10x^2 +6x +(1 -k) = 0 Using the discriminant: 6^2 -4*10*(1 -k) = 0 Solving the discriminant: k = 1/10
If x varies directly as y and x equals 24 when y equals 6 Then find x when y equals 8?
x = y/k: 24 = 6/k so k = ¼; when y = 8, x = 8/¼ = 32
3x plus y equals 4 x plus y equals 0?
x = y = 0 ?
Copyright ©2024 Infospace Holdings LLC, A System1 Company. All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Answers.