It means that a chemical reaction has taken place, and copper sulfate, carbon dioxide, and water have combined somehow.
Then there would be an "equal" sign, and on the other side of the chemical equation would be another bunch of symbols for compounds, showing what chemicals came out of the reaction.
Burning, oxidation.
Chances are the C and the H are together with multiple amounts. If so you'll get carbon dioxide (CO2) and water (H2O)
The anwer is 2 (C2H6) + 7(O2) =4 (CO2) + 6 ( H2O) left side : C=4 , H= 12, O=14 right side : C=4 , H= 12, O=14 so they are balanced.
cl2o7+h2o
h2o,Nacl,Co2,O2,O3
When copper(II) oxide (CuO) reacts with sulfuric acid (H2SO4), copper sulfate (CuSO4) and water (H2O) are produced. The balanced chemical equation for this reaction is: CuO + H2SO4 -> CuSO4 + H2O.
These are some possible ionic equation for CuSO4 plus H2O: Cu2+ + 6 H2O --> Cu(H2O)6 Cu(H2O)62+ + H2O <--> Cu(OH)(H2O)5+ + H3O+ This makes a solution of copper sulfate weakly acidic.
CH4 + 2O2 --> CO2 + 2(H2O), the products are CO2 and H2O
This is not a decomposition reaction.
The missing chemicals are 2LiOH + 2LiNO3 = H2O + CO2 + 4LiNO3.
Reaction will result in gas (CO2) andsalt formation:copper(II) sulfate CuCO3 + SO42- + 2H+ --> CO2 +CuSO4+H2O
The balanced equation is: 2 NH4Cl + Na2CO3 -> 2 NH3 + CO2 + 3 H2O + 2 NaCl
The balanced chemical equation for that reaction is: C2H6 + 7/2 O2 -> 2 CO2 + 3 H2O
The equation is: Ca(HCO3)2 + CaCO3 + CO2 + H2O -> 2CaCO3 + CO2 + H2O.
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
The balanced equation for the reaction of CO2 with H2O in the presence of energy is: CO2 + H2O + energy -> CH2O + O2
Na2CO3 (sodium carbonate) plus H2O (water) and CO2 (carbon dioxide) will undergo a chemical reaction to form sodium bicarbonate (NaHCO3). The balanced chemical equation for this reaction is: Na2CO3 + H2O + CO2 -> 2 NaHCO3.