5
The equation is #of sides x (#of sides - 3) divided by 2. Equation: N x (N-3) 2
To determine if (2, -3) is a solution of the equation ( x + 5y = 4 ), we substitute ( x = 2 ) and ( y = -3 ) into the equation. This gives us ( 2 + 5(-3) = 2 - 15 = -13 ), which does not equal 4. Therefore, (2, -3) is not a solution of the equation.
2x-3=x+2 2x-x=2+3 x=5
Let us say you X intercepts are -2 and 3 set up (X + 2)(X - 3) FOIL X^2 - X - 6 = 0 ----------------------- your parabolic equation
The value of x in the equation -2 x plus 3 4x-3 is 3.
The equation is #of sides x (#of sides - 3) divided by 2. Equation: N x (N-3) 2
The equation to solve is given by. |-2 x + 2| -3 = -3 Add 3 to both sides of the equation and simplify. |-2 x + 2| = 0 |-2 x + 2| is equal to 0 if -2 x + 2 = 0. Solve for x to obtain. So, x = 1
2 x 2 x 3 x 3
To determine if (2, -3) is a solution of the equation ( x + 5y = 4 ), we substitute ( x = 2 ) and ( y = -3 ) into the equation. This gives us ( 2 + 5(-3) = 2 - 15 = -13 ), which does not equal 4. Therefore, (2, -3) is not a solution of the equation.
2x-3=x+2 2x-x=2+3 x=5
Let us say you X intercepts are -2 and 3 set up (X + 2)(X - 3) FOIL X^2 - X - 6 = 0 ----------------------- your parabolic equation
It is a quadratic equation and can be rearranged in the form of:- x2-x-6 = 0 (x+2)(x-3) = 0 Solutions: x = -2 and x = 3
The value of x in the equation -2 x plus 3 4x-3 is 3.
The equation of a circle with center (2, -3) and radius 3 can be written as (x - 2)^2 + (y + 3)^2 = 3^2.
If there is one equation that can be solved, then (x-2)2 + (y-3)2 = 0 For an equation such as x+y-5 = 0 you will have an infinity of solutions unless you add another, independent equation and solve them simultaneously.
Good news! You don't have to do anything. [ x-3 = 2 ] is already a linear equation, and x=5 .
(x - 3) (x - square root of 2) = 0