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How Do you solve 3 to the power of 5y equals 6 to the power of y -2?
With great difficulty, do you mean 35y = 9y-2? If so then the solution is simple: 35y = 9y-2 35y = (32)y-2 35y = 32y-4 Divide both sides of the equation by 3 to eliminate the integers 5y = 2y-4 5y-2y = -4 3y = -4 Divide both sides by 3 to find the value of y y = -4/3 Substituting into the original equation: 35y = 6.594648241 x 10-4 9y-2 = 6.594648241 x 10-4 Therefore: y = -4/3 is correct.
Find the center and radius of a circle with equation X2 plus y2 plus x equals 0?
x2 + y2 - 5y + 4 = 0 x2 + y2 - 5y = - 4 x2 + y2 - 5y + 25/4 = - 4 + 25/4 = 9/4 x2 + (y - 5/2)2 = (3/2)2 Centre = (0, 5/2) and radius = 3/2
How do you expand an equation?
Multiply the coefficient by all the values inside the brackets.Example 1:2(y+1)= 2 X y + 2 X 1= 2y + 2Example 2:3 X 5y(y+4)= 3 X (5y X y) + (5y X 4)= 3 X 5y2 + 20y
What is the solution for 10x-5y equals -20 and 7x-5y equals -20?
x = 0 and y = 4
What is 9y plus 3 equals 5y plus 13?
9y+3=5y+13 4y=10 y=10/4 or 5/2 or 2.5
