With great difficulty, do you mean 35y = 9y-2? If so then the solution is simple: 35y = 9y-2 35y = (32)y-2 35y = 32y-4 Divide both sides of the equation by 3 to eliminate the integers 5y = 2y-4 5y-2y = -4 3y = -4 Divide both sides by 3 to find the value of y y = -4/3 Substituting into the original equation: 35y = 6.594648241 x 10-4 9y-2 = 6.594648241 x 10-4 Therefore: y = -4/3 is correct.
x2 + y2 - 5y + 4 = 0 x2 + y2 - 5y = - 4 x2 + y2 - 5y + 25/4 = - 4 + 25/4 = 9/4 x2 + (y - 5/2)2 = (3/2)2 Centre = (0, 5/2) and radius = 3/2
Multiply the coefficient by all the values inside the brackets.Example 1:2(y+1)= 2 X y + 2 X 1= 2y + 2Example 2:3 X 5y(y+4)= 3 X (5y X y) + (5y X 4)= 3 X 5y2 + 20y
x = 0 and y = 4
9y+3=5y+13 4y=10 y=10/4 or 5/2 or 2.5
(2, 3) is a solution only if it satisfies the equation. x + 5y = 4 (2) + 5(3) =? 4 2 + 15 =? 4 17 = 4 False Therefore, (2, 3) is not a solution to the given equation.
4
With great difficulty, do you mean 35y = 9y-2? If so then the solution is simple: 35y = 9y-2 35y = (32)y-2 35y = 32y-4 Divide both sides of the equation by 3 to eliminate the integers 5y = 2y-4 5y-2y = -4 3y = -4 Divide both sides by 3 to find the value of y y = -4/3 Substituting into the original equation: 35y = 6.594648241 x 10-4 9y-2 = 6.594648241 x 10-4 Therefore: y = -4/3 is correct.
x2 + y2 - 5y + 4 = 0 x2 + y2 - 5y = - 4 x2 + y2 - 5y + 25/4 = - 4 + 25/4 = 9/4 x2 + (y - 5/2)2 = (3/2)2 Centre = (0, 5/2) and radius = 3/2
Multiply the coefficient by all the values inside the brackets.Example 1:2(y+1)= 2 X y + 2 X 1= 2y + 2Example 2:3 X 5y(y+4)= 3 X (5y X y) + (5y X 4)= 3 X 5y2 + 20y
x = 0 and y = 4
(5y - 2)(5y + 2)
you cant
9y+3=5y+13 4y=10 y=10/4 or 5/2 or 2.5
If the inequality is > (greater than) or >= (greater than or equal to), then there are an infinite number of solutions. So let the inequality be < (less than) or <= (less than or equal to) x = 1: 5y <= 16 so y = 1, 2 or 3 x = 2: 5y <= 12 so y = 1 or 2 x = 3: 5y <= 8 so y = 1 x >= 4: 5y <= 4 no solution. So whether the inequality is < or <= there are 6 ordered pairs.
4X - 5Y = - 2- 5Y = - 4X - 2Y = (4/5)X + 2/5m(slope) = 4/5==================
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0