When you multiply two variables with different exponents, the exponents are added. For example, if you multiply x^2 by x^3, the result is x^(2+3) = x^5. Similarly, if you multiply x^3 by x^(-2), the result is x^(3+(-2)) = x^1 = x.
Assuming the bases are the same, you add the exponents. 10^3 x 10^3 = 10^6
The algebraic expression for x times x is x2 ( x squared).
2 x 2 x 3 x 3
Multiply 2 x 2 x 3 x 3
When you multiply two variables with different exponents, the exponents are added. For example, if you multiply x^2 by x^3, the result is x^(2+3) = x^5. Similarly, if you multiply x^3 by x^(-2), the result is x^(3+(-2)) = x^1 = x.
Assuming the bases are the same, you add the exponents. 10^3 x 10^3 = 10^6
The algebraic expression for x times x is x2 ( x squared).
Question: 2 x 3 x 4 Answer: It's easier to break this down into separate parts. First, multiply 2 x 3 = 6 Then multiply 6 (which is 2 x 3) x 4 = 24 Therefore, 2 x 3 x 4 = 24
2 x 2 x 3 x 3
Multiply 2 x 2 x 3 x 3
1 x 9, 3 x 3
1 x 9, 3 x 3.
3 x 3 x 11
8
The prime factors are 2 x 3 x 3 x 5.
The problem to solve is: xy+x+3y+3 Multiply y and x Multiply the y and x Multiply y and x The y just gets copied along. The x just gets copied along. The answer is yx yx x*y evaluates to yx x*y+x evaluates to yx+x Multiply y and 3 Multiply y and 1 The y just gets copied along. The answer is y y 3*y evaluates to 3y The answer is yx+x+3y x*y+x+3*y evaluates to yx+x+3y The answer is yx+x+3y+3 x*y+x+3*y+3 evaluates to yx+x+3y+3 ---- The final answer isyx+x+3y+3----