2xy=2*30*2=120
15xy-2xy-7x+x=13xy-6x
No, it equals -2xy. lrn2math
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
2xy=2*30*2=120
2xy substitute 3 for y and 5 for x 2(5)(3) = 30
15xy-2xy-7x+x=13xy-6x
No, it equals -2xy. lrn2math
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
-2x - 2y = -122x + 2y = 122y = 12 - 2xy = 6 - x
It's an hyperbola equation.
The greatest common factor of 4xy and -6xy is 2xy. To find the greatest common factor, we first factor out the numbers 4 and -6 to get 2(2xy) and -2(3xy). The greatest common factor is the highest common factor that divides both terms evenly, which in this case is 2xy.
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
Y=15/(2c+2x)
Because 2x+y is addition not multiplication
x2 + y2 = x2 - 2xy + y2 + 2xy = (x - y)2 + 2xy = 72 + 2*8 = 49 + 16 = 65 You could, instead, solve the two equations for x and y and substitute, but the above method is simpler.