0.125
Let the two numbers be represented by a and b. Then, ab = 112 so b = 112/a. And, a + b = -32......substituting for b this becomes :- a + 112/a = -32........multiplying throughout by a a2 + 112 = -32a.......re-arranging a2 + 32a + 112 = 0 This equation factors (a + 4)(a + 28) = 0 When (a + 4) = 0 then a = -4......and thus b = -28 When (a + 28) = 0 then a = -28....and thus b = -4 The two numbers are -4 and -28.
112c
112
280
0.125
112 - 35 + 77 = 0
Let the two numbers be represented by a and b. Then, ab = 112 so b = 112/a. And, a + b = -32......substituting for b this becomes :- a + 112/a = -32........multiplying throughout by a a2 + 112 = -32a.......re-arranging a2 + 32a + 112 = 0 This equation factors (a + 4)(a + 28) = 0 When (a + 4) = 0 then a = -4......and thus b = -28 When (a + 28) = 0 then a = -28....and thus b = -4 The two numbers are -4 and -28.
112c
Either (a) multiply 112 by 0, by 1, by 2, etc., or (b) starting with zero, add 112 repeatedly to get the following numbers in the sequence of multiples.
how do you solve the questions to this sequence 0, 10, 24, 56, 112, 190
112
0, 112, 60.
Shan-Xi can be found at 38° 0′ 0″ N, 112° 0′ 0″ E.
7X^2 -56X + 112 = 0 divide through by 7 X^2 - 8X + 16 = 0 factor (X-4)(X-4) X = 4
36° 6′ 0″ N, 112° 6′ 0″ W36.1, -112.1
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